Question

我正在开发一个应用程序，它将绘制的画布作为jpeg图像存储在SD卡中。问题是当我试图查看保存的图像时，它加载的时间比其他图像要多，我希望保存的图像在正常时间内像其他图像一样被查看我保存图片的代码是：

            View content = drawView;
            content.setDrawingCacheEnabled(true);
            content.setDrawingCacheQuality(View.DRAWING_CACHE_QUALITY_LOW);
            Bitmap bitmap = content.getDrawingCache();

            String path = Environment.getExternalStorageDirectory().getAbsolutePath();
            String file_name="Imatge"+System.currentTimeMillis()+".jpg";
            File file = new File(path,file_name);
            FileOutputStream ostream;
            try {                   
                ostream = new FileOutputStream(file);
                bitmap.compress(CompressFormat.PNG,50, ostream);
                ostream.flush();
                ostream.close();
                Toast.makeText(getApplicationContext(), " :) Image saved in "+ path+"/"+file_name, 5000).show();
            } catch (Exception e) {
                e.printStackTrace();
                Toast.makeText(getApplicationContext(), e.toString()+"error", 5000).show();
            }
                }

先谢谢，请帮帮我!!!!

Answer 1

您的代码将图像保存为PNG文件（即使您为其指定了文件扩展名.jpg）。 PNG文件是无损的，因此比JPEG文件大得多。

要解决此问题，请将其另存为JPEG格式：

ostream = new FileOutputStream(file);
bitmap.compress(CompressFormat.JPEG, 50, ostream);

Answer 2

使用如下所示

        String extStorageDirectory = Environment.getExternalStorageDirectory().toString();
                     FileOutputStream out = null;
                     Log.e("h",""+mview.getMeasuredHeight()+" "+mview.getMeasuredWidth());
                    try {
                         out = new FileOutputStream(new File(extStorageDirectory + "/myAwesomeDrawing.jpg"));
                         mBitmap.compress(Bitmap.CompressFormat.JPEG, 90, out); 
                         out.flush(); 
                         out.close();
                    } catch (Exception e) {
                        // TODO Auto-generated catch block
                        e.printStackTrace();
                    }

其中 mBitmap 是您在 Drawview 类中使用的Gloabal变量，因此使用此必须跳过此行menas在此行注释

  /*View content = drawView;
     content.setDrawingCacheEnabled(true);
        content.setDrawingCacheQuality(View.DRAWING_CACHE_QUALITY_LOW);
        Bitmap bitmap = content.getDrawingCache();
*/

可能有效吗

Answer 3

我自己找到解决方案，解决方案是通过媒体商店存储图像，这是我的代码正常工作

View content = drawView;
                content.setDrawingCacheEnabled(true);
                content.setDrawingCacheQuality(View.DRAWING_CACHE_QUALITY_AUTO);
                Bitmap bitmap;
                bitmap = content.getDrawingCache();             
                String file_name="MyImage"+System.currentTimeMillis()+".jpg";

                ContentValues values = new ContentValues();
                values.put(Images.Media.TITLE,"MyImage");                   
                values.put(Images.Media.DESCRIPTION,"Advanced Practice");                   
                values.put(Images.Media.MIME_TYPE, "image/jpeg");
                Uri url = null;

                try 
                {   
                    url = getContentResolver().insert(MediaStore.Images.Thumbnails.getContentUri("external"), values);
                    MediaStore.Images.Media.insertImage(getContentResolver(), bitmap,"MyImage","Advanced Practice");                     
                    Toast.makeText(getApplicationContext(), " :) Image saved in /sdcard/DCIM/Camera/"+file_name, 5000).show();
                } 
                catch (Exception e) 
                {
                    e.printStackTrace();
                    Toast.makeText(getApplicationContext(), e.toString()+"error", 5000).show();
                }

稍后保存了jpeg

3 个答案: