Tkinter按钮绑定和父级销毁

时间:2009-07-03 05:58:38

标签: python tkinter

这是我的代码:

    print '1'
from Tkinter import *
print '2'
class myApp:

    print '3'
    def __init__(self,parent):
        print '4'

##        self.myparent = parent    line1
        print '11'

        self.myContainer1 = Frame(parent)
        print '12'
        self.myContainer1.pack()
        print '13'

        self.button1 = Button(self.myContainer1,text="OK",background="green")
        print '14'
        self.button1.pack(side=LEFT)
        print '15'
        self.button1.bind("<Button-1>",self.button1Click)
        print '16'

        self.button2 = Button(self.myContainer1,text="Cancel",background="cyan")
        print '17'
        self.button2.pack(side=RIGHT)
        print '18'
        self.button2.bind("<Button-1>",self.button2Click)
        print '19'


    def button1Click(self,event):

            print '5'

            if self.button1['background'] == 'green':
                print '20'
                self.button1['background'] ='tan'
                print '21'

            else:

                print '22'

                self.button1['background'] = 'yellow'

                print '23'

    def button2Click(self,event):

            print '6'

##            self.myparent.destroy()

            self.parent.destroy()

print '7'
root = Tk()
print '8'
myapp = myApp(root)
print '9'
root.mainloop()
print '10'

错误是:

    >>> ================================ RESTART ================================
>>> 
1
2
3
7
8
4
11
12
13
14
15
16
17
18
19
9
5
20
21
5
22
23
6
Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Python26\lib\lib-tk\Tkinter.py", line 1403, in __call__
    return self.func(*args)
  File "C:\Documents and Settings\he00044.HALEDGEWOOD\Desktop\TkinterExamples\buttonBind.py", line 56, in button2Click
    self.parent.destroy()
AttributeError: myApp instance has no attribute 'parent'
10
>>> 

这是我评论第1行

的时候

可能是becoz myapp没有找到父母。

但这个概念并不清楚。

任何人都可以详细解释这个概念......

4 个答案:

答案 0 :(得分:2)

为什么你曾经评论过提及self.myparent的那两行,并创建一个提到一个神秘的,从未初始化的self.parent?当然,这是你问题的开始 - 看起来像是荒谬的,蓄意的破坏代码。

答案 1 :(得分:0)

将传入参数parent分配给self.parent?

def __init__(self,parent):
    self.parent = parent

答案 2 :(得分:0)

你的问题不是与tkinter有关,而是与面向对象的设计有关。

myApp 具有 __ init __ 方法(构造函数,创建该类对象时执行的方法),以及按钮单击的两种方法。在button2Click方法中,您尝试读取属性 self.parent (翻译为 myapp.parent ),但未定义此属性。

取消注释第1行时,您不会收到错误。这是因为您正在创建属性 myapp.parent ,并且您正在将Tk根小部件分配给此属性。这是必要的,因为您创建的所有窗口小部件都必须接收其父窗口小部件。

答案 3 :(得分:0)

到目前为止,其他答案都很棒。
这也可能有所帮助:Fredrik Lundh's intro to Tkinter

为您的代码添加了一些注释,以及其他答案,可以帮助您再次移动:

import Tkinter

class MyApp:
    def __init__(self, parent): # constructor
        self.parent = parent # the parent here is 'root'
        self.myContainer1 = Tkinter.Frame(self.parent) # create Frame w/ root as parent
        self.myContainer1.pack() # make Frame (myContainer1) visible
        self.button1 = Tkinter.Button(self.myContainer1, 
                        text="OK", background="green") # add button as child of Frame
        self.button1.pack(side=Tkinter.LEFT) # place button1 in Frame
        self.button1.bind("<Button-1>",self.button1Click) # bind left mouse button to button1Click method
        self.button2 = Tkinter.Button(self.myContainer1, text="Cancel", 
                        background="cyan")
        self.button2.pack(side=Tkinter.RIGHT)
        self.button2.bind("<Button-1>", self.button2Click)

    def button1Click(self, event):
        if self.button1['background'] == 'green':
            self.button1['background'] ='tan'
        else:
            self.button1['background'] = 'yellow'

    def button2Click(self, event):
        self.parent.destroy() # the parent here is 'root', so you're ending the event loop

root = Tkinter.Tk()     # create root widget (a window)
myapp = MyApp(root)     # create instance of MyApp with root as the parent
root.mainloop()         # create event loop (ends when window is closed)