具有错误处理的Geopy

时间:2012-05-27 20:02:37

标签: python geopy

我有一些错误处理的Python代码,但由于某些原因,代码似乎仍然无法处理这个特定的错误:

raise GQueryError("No corresponding geographic location could be found for the     specified location, possibly because the address is relatively new, or because it may be incorrect.")
geopy.geocoders.google.GQueryError: No corresponding geographic location could be found for the specified location, possibly because the address is relatively new, or because it may be incorrect.

这是来源:

import csv
from geopy import geocoders
import time

g = geocoders.Google()

spamReader = csv.reader(open('locations.csv', 'rb'), delimiter='\t', quotechar='|')

f = open("output.txt",'w')

for row in spamReader:
    a = ', '.join(row)
    #exactly_one = False
    time.sleep(1)

    try:
        place, (lat, lng) = g.geocode(a)
    except ValueError:
        #print("Error: geocode failed on input %s with message %s"%(a, error_message))
        continue 

    b = str(place) + "," + str(lat) + "," + str(lng) + "\n"
    print b
    f.write(b)

我没有包含足够的错误处理吗?我的印象是"除了ValueError"会处理这种情况,但我一定是错的。

提前感谢您的帮助!

P.S。我把它从代码中删除了,但我不知道它到底意味着什么:

   def check_status_code(self,status_code):
    if status_code == 400:
        raise GeocoderResultError("Bad request (Server returned status 400)")
    elif status_code == 500:
        raise GeocoderResultError("Unkown error (Server returned status 500)")
    elif status_code == 601:
        raise GQueryError("An empty lookup was performed")
    elif status_code == 602:
        raise GQueryError("No corresponding geographic location could be found for the specified location, possibly because the address is relatively new, or because it may be incorrect.")
    elif status_code == 603:
        raise GQueryError("The geocode for the given location could be returned due to legal or contractual reasons")
    elif status_code == 610:
        raise GBadKeyError("The api_key is either invalid or does not match the domain for which it was given.")
    elif status_code == 620:
        raise GTooManyQueriesError("The given key has gone over the requests limit in the 24 hour period or has submitted too many requests in too short a period of time.")

1 个答案:

答案 0 :(得分:5)

现在try / except只捕捉ValueError s。要同时捕获GQueryError,请将except ValueError:行替换为:

except (ValueError, GQueryError):

或者如果GQueryError不在你的命名空间中,你可能需要这样的东西:

except (ValueError, geocoders.google.GQueryError):

或者捕获ValueError以及check_status_code中列出的所有错误:

except (ValueError, GQueryError, GeocoderResultError, 
        GBadKeyError, GTooManyQueriesError):

(同样,如果错误位置不在您的命名空间中,请将geocoders.google.或错误位置添加到所有地理错误的前面。)

或者,如果您只想捕获所有可能的异常,您可以这样做:

except:

但这通常是不好的做法,因为它也会在你的place, (lat, lng) = g.geocode(a)行中发现语法错误,你不想抓住它,所以最好检查一下geopy代码来找到所有的它可能会抛出你想抓住的可能例外。希望所有这些都列在你找到的那段代码中。