如何在转换为Unix时指定时区(UTC)? (蟒蛇)

时间:2009-07-03 00:00:45

标签: python datetime iso8601 unix-timestamp

我有一个IS8601格式的utc时间戳,我试图将其转换为unix时间。这是我的控制台会话:

In [9]: mydate
Out[9]: '2009-07-17T01:21:00.000Z'
In [10]: parseddate = iso8601.parse_date(mydate)

In [14]: ti = time.mktime(parseddate.timetuple())

In [25]: datetime.datetime.utcfromtimestamp(ti)
Out[25]: datetime.datetime(2009, 7, 17, 7, 21)
In [26]: datetime.datetime.fromtimestamp(ti)
Out[26]: datetime.datetime(2009, 7, 17, 2, 21)

In [27]: ti
Out[27]: 1247815260.0
In [28]: parseddate
Out[28]: datetime.datetime(2009, 7, 17, 1, 21, tzinfo=<iso8601.iso8601.Utc object at 0x01D74C70>)

如你所见,我无法回到正确的时间。如果我使用fromtimestamp(),则小时提前一个,如果我使用utcfromtimestamp()

,它提前六小时

有什么建议吗?

谢谢!

4 个答案:

答案 0 :(得分:13)

您可以使用datetime.utctimetuple()在UTC中创建struct_time,然后将其转换为带calendar.timegm()的unix时间戳:

calendar.timegm(parseddate.utctimetuple())

这也会处理任何夏令时偏移,因为utctimetuple()会对此进行规范化。

答案 1 :(得分:0)

我只是猜测,但是由于时区的原因,一小时的差异可能不是因为夏令时开启/关闭。

答案 2 :(得分:0)

naive_utc_dt = parseddate.replace(tzinfo=None)
timestamp = (naive_utc_dt - datetime(1970, 1, 1)).total_seconds()
# -> 1247793660.0

another answer to similar question中查看更多详情。

然后回来:

utc_dt = datetime.utcfromtimestamp(timestamp)
# -> datetime.datetime(2009, 7, 17, 1, 21)

答案 3 :(得分:0)

import time
import datetime
import calendar

def date_time_to_utc_epoch(dt_utc):         #convert from utc date time object (yyyy-mm-dd hh:mm:ss) to UTC epoch
    frmt="%Y-%m-%d %H:%M:%S"
    dtst=dt_utc.strftime(frmt)              #convert datetime object to string
    time_struct = time.strptime(dtst, frmt) #convert time (yyyy-mm-dd hh:mm:ss) to time tuple
    epoch_utc=calendar.timegm(time_struct)  #convert time to to epoch
    return epoch_utc

#----test function --------
now_datetime_utc = int(date_time_to_utc_epoch(datetime.datetime.utcnow()))
now_time_utc = int(time.time())

print (now_datetime_utc)
print (now_time_utc)

if now_datetime_utc == now_time_utc : 
    print ("Passed")  
else : 
    print("Failed")