如何使用PHP从字符串中删除子字符串？

Question

给出以下字符串

http://thedude.com/05/simons-cat-and-frog-100x100.jpg

我想使用substr或trim（或您认为更合适的任何内容）返回此

http://thedude.com/05/simons-cat-and-frog.jpg

即删除-100x100。我需要的所有图像都会在扩展名之前标记到文件名的末尾。

似乎在SO和Ruby和Python上有这样的响应，但不是PHP /特定于我的需求。

How to remove the left part of a string?

Remove n characters from a start of a string

Remove substring from the string

有什么建议吗？

Answer 1

如果您想匹配任何宽度/高度值：

  $path = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg";

  // http://thedude.com/05/simons-cat-and-frog.jpg
  echo preg_replace( "/-\d+x\d+/", "", $path );

演示：http://codepad.org/cnKum1kd

使用的模式非常基本：

/     Denotes the start of the pattern
-     Literal - character
\d+   A digit, 1 or more times
x     Literal x character
\d+   A digit, 1 or more times
/     Denotes the end of the pattern

Answer 2

$url = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg";
$new_url = str_replace("-100x100","",$url);

Answer 3

$url = str_replace("-100x100.jpg", '.jpg', $url);

使用-100x100.jpg进行防弹解决方案。

Answer 4

如果-100x100是您尝试从所有字符串中删除的唯一字符，为什么不使用str_replace？

$url = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg";
str_replace("-100x100", "", $url);