Question

我很想知道在为新项目类型制作MonoDevelop Addins时如何将“复制到输出目录”选项设置为“复制如果更新”？

以这段代码为例，...我需要添加什么才能在构建时将“manifest.json”复制到输出目录？

<?xml version="1.0"?>
<Template originator = "Andrew Witte">

    <TemplateConfiguration>
        <_Name>MonoNaCl Project</_Name>
        <_Category>C#/MonoNaCl</_Category>
        <LanguageName>C#</LanguageName>
        <_Description>Creates a MonoNaCl project.</_Description>
    </TemplateConfiguration>

    <!-- Actions -->
    <Actions>
        <Open filename = "Internal.c"/>
        <Open filename = "Main.cs"/>
    </Actions>

    <Combine name = "${ProjectName}" directory = ".">
        <Options>
            <StartupProject>${ProjectName}</StartupProject>
        </Options>
        <References>
            <Reference type="Gac" refto="System" />
        </References>
        <Project name = "${ProjectName}" directory = "." type = "MonoNaCl">
            <Options Target = "Exe"/>
            <Files>
<File name="manifest.json">
<![CDATA[{
"name": "MonoNaCl",
  "description": "Mono for NaCl project.",
  "version": "1.0.0",
  "icons": {
  },
  "requirements": {
    "3D": {
      "features": ["css3d", "webgl"]
    }
  },
  "app": {
    "launch": {
      "local_path": "${ProjectName}.html"
    }
}
}
]]></File>
</Files>
        </Project>
    </Combine>
</Template>

Answer 1

目前无法为modifying core添加属性或registering a custom template type。

但是，TBH而不是copy-to-output我会使用自定义构建操作和构建扩展来复制带有该构建操作的文件。

MonoDevelop Addin：如何在＆＃34; xpt.xml＆＃34;中设置CopyToOutput构建选项。文件

1 个答案: