Question

我已经创建了一个关系请求页面，现在我遇到的问题是当我关系处于活动状态时，它会继续显示在视图中。我只希望显示字段active = false的请求。

这是我的请求控制器，它因阵列而崩溃，我该如何解决这个问题呢？

public function request(){
        $this->set('title_for_layout', 'Relationships');
        $this->set('stylesheet_used', 'homestyle');
        $this->set('image_used', 'eBOXLogoHome.jpg');   
        $this->layout='home_layout';
        $userid = $this->Auth->user('username');
        $this->set('Relationships', $this->Relationship->find('all', array('conditions' => array('Relationship.partytwo' => $userid)) array('conditions'=>array('Relationship.active'=false))));

    }

giggles，这是我的观点

<?php foreach($Relationships as $relationship):?>
                    <tr> 

                        <td align='center'><?php echo $relationship['Relationship']['partyone']; ?></td>
                        <td align='center'><?php echo $relationship['Relationship']['partytwo']; ?></td>
                        <td> </td>
                        <td><?php echo $this->Html->link($relationship['Relationship']['partyone'], array('action'=>'approve', $relationship['Relationship']['id'])); ;?>
                        </td>

                    </tr>
                <?php endforeach; ?>

            </table>

Answer 1

尝试使用set语句：

$this->set('Relationships', $this->Relationship->find('all', 
  array('conditions' => array(
    'Relationship.partytwo' => $userid,
    'Relationship.active' => false)
  )
));

cakephp显示特定条件的数据

1 个答案: