Question

如何查看前两行的第一行

表1

id  name     value size   result
----------------------------------
001 rajan    100   280DD   100%
002 Vijayan  200   120DD    80%
003 Sidarth  300   150DD    90%
004 Rakesh   400   270DD    95%
...

我想选择前两行到单行......

预期产出

id id name name value value size size result result
---------------------------------------------------------    
001 002 rajan vijayan 100 200 280DD 120DD 100% 80%
003 004 Sidarth Rakesh 300 400 150DD 270DD 90% 95%
.....

怎么做？

Answer 1

SELECT 
    t.Id, tt.Id, t.name, tt.name, t.value, tt.value, t.size, tt.size, t.result, tt.result
FROM YourTable t
INNER JOIN YourTable tt ON tt.Id = t.Id + 1
WHERE tt.Id % 2 = 0

这对我有用。希望对你有所帮助。

如果你需要帮助，请试试。

Declare @TempTable as table (FirstId int, SecondId int null, FirstCaption nvarchar(max), SecondCaption nvarchar(max) null, FirstDescription nvarchar(max), SecondDescription nvarchar(max) null)

DECLARE @TempId int DECLARE curs CURSOR FOR 从类别中选择ID 打开诅咒从curs获取下一个到@TempId WHILE @@ FETCH_STATUS = 0 开始 IF（@TempId％2 = 1）开始插入@TempTable 选择 t.Id，null，t.Caption，null，t.Description，null 来自类别t 在哪里.Id = @TempId

    END
ELSE
    BEGIN
        UPDATE @TempTable SET SecondId = t.Id, SecondCaption = t.Caption, SecondDescription = t.Description
        FROM categories t
        INNER JOIN @TempTable tt ON tt.FirstId = @TempId - 1
        WHERE t.Id = @TempId
    END
fetch next from curs into @TempId

端关闭诅咒 deallocate curs

SELECT * FROM @TempTable

Answer 2

with cte as (
select row_number() over (order by id) as rn,
* from Table1
)
select a.id, b.id, a.name, a.value, b.value, a.size, b.size, a.result, b.result
from cte a join cte.b on a.id = b.id - 1

where a.rn <insert your criteria for which to show, for example in (1,3,5,7) or a modulus operator to see every 2nd row to avoid duplicate data>

如何查看前两行到单行

2 个答案: