尽管“cin.get();”,控制台窗口仍不会停留在屏幕上或系统(“暂停”)

时间:2012-05-26 01:10:34

标签: c++ console main

我希望每当你运行C ++程序时弹出控制台窗口......但是在我的代码中没有发生这种情况。它很快消失了。怎么了?注意:我是C ++的新手。

由于某些原因,当我仅使用main()函数来保存所有内容而没有第二个函数时,它可以正常工作,但出于我的任务目的,我无法将所有内容都填入main()

#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <sstream>
#include <cstdio>
using namespace std;

ifstream file("maze.txt");
vector<char> vec(istreambuf_iterator<char>(file), (istreambuf_iterator<char>())); // Imports characters from file
vector<char> path;                      // Declares path as the vector storing the characters from the file
int x = 18;                             // Declaring x as 18 so I can use it with recursion below
char entrance = vec.at(16);             // 'S', the entrance to the maze
char firstsquare = vec.at(17);          // For the first walkable square next to the entrance
vector<char> visited;                   // Squares that we've walked over already

int main()
{
    if (file) {
        path.push_back(entrance);               // Store 'S', the entrance character, into vector 'path'
        path.push_back(firstsquare);            // Store the character of the square to the right of the entrance
                                                // into vector 'path'.
        while (isalpha(vec.at(x)))
        {
            path.push_back(vec.at(x));
            x++;
        }
    }
}

int printtoscreen()
{
    cout << "Path is: ";                    // Printing to screen the first part of our statement

        // This loop to print to the screen all the contents of the vector 'path'.
        for(vector<char>::const_iterator i = path.begin(); i != path.end(); ++i)  // 
        {
        std::cout << *i << ' ';
        }

        cout << endl;
        cin.get();                          // Keeps the black box that pops up, open, so we can see results.
        return 0;
}

2 个答案:

答案 0 :(得分:6)

也许如果您实际上调用 printtoscreen,您可能会发现它执行暂停的代码。

但是,事实上,无论如何,我都会将cin.get()位放在main的末尾,因为它只是在IDE中运行时才有的东西。你可能不会想要它在最终的可执行文件中,因为它可能会惹恼任何试图运行它的人。

换句话说,从cin.get();的末尾删除printtoscreen,并在main末尾添加类似内容:

cout << "Press ENTER to exit (remember to remove this from production code)"
     << endl;
cin.get();

请注意,您可能需要将printtoscreen移至main之前,或在main之前为其提供原型(以便main知道它)。

答案 1 :(得分:1)

您没有呼叫printoscreen功能。尝试在printtoscreen();功能结束前添加main()

编辑:

另请考虑在此函数中将int printoscreen(){更改为void printoscreen(){并相应地return 0;更改为return;,因为您没有返回任何有意义的内容,并且在主要内容中是ignorig结果值。所以enitre代码将是:

#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <sstream>
#include <cstdio>
using namespace std;

ifstream file("maze.txt");
vector<char> vec(istreambuf_iterator<char>(file), (istreambuf_iterator<char>())); // Imports characters from file
vector<char> path;                      // Declares path as the vector storing the characters from the file
int x = 18;                             // Declaring x as 18 so I can use it with recursion below
char entrance = vec.at(16);             // 'S', the entrance to the maze
char firstsquare = vec.at(17);          // For the first walkable square next to the entrance
vector<char> visited;                   // Squares that we've walked over already

void printtoscreen();

int main()
{
    if (file) {
        path.push_back(entrance);               // Store 'S', the entrance character, into vector 'path'
        path.push_back(firstsquare);            // Store the character of the square to the right of the entrance
                                                // into vector 'path'.
        while (isalpha(vec.at(x)))
        {
            path.push_back(vec.at(x));
            x++;
        }
    }
    printtoscreen();
}

void printtoscreen()
{
    cout << "Path is: ";                    // Printing to screen the first part of our statement

        // This loop to print to the screen all the contents of the vector 'path'.
        for(vector<char>::const_iterator i = path.begin(); i != path.end(); ++i)  // 
        {
        std::cout << *i << ' ';
        }

        cout << endl;
        cin.get();                          // Keeps the black box that pops up, open, so we can see results.
        return;
}