VideoCapture文件名

Question

我是新来的，这是我的第一篇文章。我在VideoCapture中遇到了问题：我希望在“for”功能中自动更改图片的名称，并将图片保存在我选择的目录中，但我无法弄清楚我要做什么并没有在互联网上找到它。如果有人知道，请帮助我。以下是命令行的示例：

from VideoCapture import Device
cam = Device()
cam.saveSnapshot('here i want to call a variable, but i don't know how.jpg')

就是这样。我也不知道在哪里写这个目录。

由于

Answer 1

在C ++中，您通常会将字符串与ostringstream组合在一起，如下所示：

std::ostringstream filename;

for (int i=0; i<10; i++) {
    filename << "variable: " << i << ".jpg";
    cam.saveSnapshot(filename.str().c_str());
}

目前还不完全清楚你在用C ++做什么部分（如果有的话）以及用Python做什么......

Answer 2

saveSnapshot()方法作为第一个非self参数，采用文件名。
参考：http://videocapture.sourceforge.net/html/VideoCapture.html

这意味着你可以这样做：

import os
from VideoCapture import Device

save_dir = '/path/to/my/img/dir' # or for windows: `c:/path/to/my/img/dir` 
img_file_name = 'an_image.jpg'

cam = Device()
cam.saveSnapshot( os.path.join(save_dir, img_file_name) )

Answer 3

好的，这很简单。

from VideoCapture import Device
from os.path import join, exists
# We need to import these two functions so that we can determine if
# a file exists.

import time
# From your question I'm implying that you want to execute the snapshot
# every few seconds or minutes so we need the time.sleep function.

cam = Device()

# First since you want to set a variable to hold the directory into which we
# will be saving the snapshots.
snapshotDirectory = "/tmp/" # This assumes your on linux, change it to any 
# directory which exists.

# I'm going to use a while loop because it's easier...
# initialize a counter for image1.jpg, image2.jpg, etc...
counter = 0

# Set an amount of time to sleep!
SLEEP_INTERVAL = 60 * 5 # 5 minutes!

while True:

    snapshotFile = join(snapshotDirectory, "image%i.jpg" % counter)
    # This creates a string with the path "/tmp/image0.jpg"
    if not exists(snapshotFile):
        cam.saveSnapshot(snapshotFile)
        time.sleep(SNAPSHOT_INTERVAL)
    # if the snapshot file does not exist then create a new snapshot and sleep
    # for a few minutes.

    #finally increment the counter.
    counter = counter + 1

就是这样，那应该完全符合你的要求。