Question

我正在编写java / spring webapp，其中每个用户都可以拥有自己的单词列表。每当用户添加/删除一个单词时，就会有一个ajax调用，它发送一个带有这个单词的JSON来添加/删除，当服务器端完成时，则返回JSON对象中的当前单词列表到jQuery。

一切正常。对于小JSON单词列表，添加和删除非常快，但是当单词列表变大时，ajax调用变得更慢。添加/删除呼叫将非常频繁。

JSON单词列表示例[polish words]：

 [{"word":"abrys","wordId":646},{"word":"acpan","wordId":647},
 {"word":"akrania","wordId":457},{"word":"akwawita","wordId":648},
 {"word":"amalgamat","wordId":399},{"word":"amurski","wordId":465},
 {"word":"amurskie","wordId":1030},{"word":"ananke","wordId":649},
 {"word":"androlog","wordId":650}]

jQuery [或多或少]：

$("#add_word_submit").live("click", function(e) {
    e.preventDefault();
    var word = $('#add_word').serializeObject();
    $.postJSON("word.html", word, function(words) {
        showDividedAccountWords(words);     
    });
});

$(".delete_button").live("click", function(e) {
    e.preventDefault();
    if(confirm(Main.confirmWordDelete)) {
        var wordId = $(this).attr("id").substring("delete_".length);
        wordName["word"] = $(this).children("img").attr("alt");
        $.ajax({
            type: "DELETE",
            url: "word/" + wordId + ".html",
            success: function(words) {
                showDividedAccountWords(words);
            }
        }); 
    }
});

的Java /弹簧：

@RequestMapping(value="/word", method = RequestMethod.POST)
public @ResponseBody List<Word> addNewWord(@RequestBody Word word, Principal principal) {
    wordService.addNewWord(word, principal.getName());
    return getCurrentWords(principal.getName());
}

@RequestMapping(value="/word/{wordId}", method = RequestMethod.DELETE)
public @ResponseBody List<Word> deleteWord(@PathVariable Long wordId, Principal principal) {
    wordService.deleteWord(wordId, principal.getName());
    return getCurrentWords(principal.getName());
}

public List<Word> getCurrentWords(String username) {
    List<Word> accountWords = new ArrayList<Word>();
    accountWords.addAll(wordService.listUserWords(username));
    return accountWords;
}

你可以给我一些提示来重构它吗？也许每次用户添加/删除单词时我都不应该返回当前的单词列表？

Answer 1

要向列表中逐步添加单词对象，请将新单词传递给服务器，并让它只返回一个（word：wordid）对象。然后，您可以将其添加到现有列表中，并按如下方式对其进行排序：

var words=[{"word":"abrys","wordId":646},{"word":"acpan","wordId":647},
 {"word":"akrania","wordId":457},{"word":"akwawita","wordId":648},
 {"word":"amalgamat","wordId":399},{"word":"amurski","wordId":465},
 {"word":"amurskie","wordId":1030},{"word":"ananke","wordId":649},
 { "word": "androlog", "wordId": 650}];


var result = { "word": "aklina", "wordid": "702" }; // returned by server from AJAX call
words.push(result); 

words.sort(
  function(a, b) {
    return a.word.localeCompare(b.word);
  }
 );

Answer 2

我会让java / spring处理信息，但只返回一个小字符串，以查看延迟是否在数据传输中。如果java / spring处理数据没有实质性差异，那么它可以在transfer或jquery处理中。您可以通过让jQuery在传输完成时向控制台发送警报来测试它。如果速度很快，则必须使用jQuery处理较长的数据数据。

重构大型JSON多次调用

2 个答案: