如何从URL加载图像然后将其放入DataGridView的单元格(而不是列标题)?包含图像的行将在运行时基于来自Web服务的搜索添加到视图中。无法找到针对此特定目的的答案......帮助!
首先我尝试使用PictureBox。当从Web服务接收事件时,我将循环到结果以添加行,每行包括一个图像。
// Add image
System.Windows.Forms.PictureBox picEventImage = new System.Windows.Forms.PictureBox();
picEventImage.Image = global::MyEventfulQuery.Properties.Resources.defaultImage;
picEventImage.ImageLocation = Event.ImageUrl;
this.dgvEventsView.Controls.Add(picEventImage);
picEventImage.Location = this.dgvEventsView.GetCellDisplayRectangle(1, i, true).Location;
即使图像加载完美,它看起来也与视图断开连接,即当我滚动时图像不会移动,而当用新数据刷新视图时,图像只是徘徊......糟糕。
所以我尝试了其他帖子的提示:
Image image = Image.FromFile(Event.ImageUrl);
DataGridViewImageCell imageCell = new DataGridViewImageCell();
imageCell.Value = image;
this.dgvEventsView[1, i] = imageCell;
但我说错了 “不支持URI格式。”
答案 0 :(得分:3)
看一下这篇SO帖子https://stackoverflow.com/a/1906625/763026
foreach (DataRow row in t.Rows)
{
HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create(row["uri"].ToString());
myRequest.Method = "GET";
HttpWebResponse myResponse = (HttpWebResponse)myRequest.GetResponse();
System.Drawing.Bitmap bmp = new System.Drawing.Bitmap(myResponse.GetResponseStream());
myResponse.Close();
row["Img"] = bmp;
}
答案 1 :(得分:-2)
表格活动:
Private con As New SqlConnection("YourConnectionString")
Private com As SqlCommand
Private Sub DGV_CellClick(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellEventArgs) Handles DGV.CellClick
con.Open()
com = New SqlCommand("SELECT MyPhoto FROM tbGalary WHERE ID=" & DGV.Rows(e.RowIndex).Cells(0).Value, con)
Dim ms As New MemoryStream(CType(com.ExecuteScalar, Byte()))
txtPicture.Image = Image.FromStream(ms)
txtPicture.SizeMode = PictureBoxSizeMode.StretchImage
com.Dispose()
con.Close()
End Sub
SQL表:
CREATE TABLE [dbo].[tbGalary](
[ID] [int] NOT NULL,
[MyPhoto] [image] NOT NULL
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
SQL插入图片:
INSERT INTO tbGalary VALUES('1','D:\image1.jpg')
INSERT INTO tbGalary VALUES('2','D:\image2.jpg')
INSERT INTO tbGalary VALUES('3','D:\image3.jpg')
INSERT INTO tbGalary VALUES('4','D:\image4.jpg')
INSERT INTO tbGalary VALUES('5','D:\image5.jpg')
<强>结果强>
视频链接:Retrieve an image in DataGridView load to PictureBox in VB.NET