Question

所以我有一个名为“maze.txt”的文本文件，如下所示：

###############
Sacbifnsdfweovw
###############

我想检查左上角的字母是否是'S'，然后检查右边的字母是否是字母字符。然后，我将继续检查前一个字母后面的字符是否是字母字符。这些字母将存储在我的矢量“路径”中。最后，我将打印以筛选我们经历过的每个字母。但出于某种原因，对于上面的那一大块字母，屏幕只打印出'S'和'a'，而没有打印出其他字母。怎么了？这是我的代码：

int main()
{
    ifstream file("maze.txt");
    if (file) {
        vector<char> vec(istreambuf_iterator<char>(file), (istreambuf_iterator<char>())); // Imports characters from file
        vector<char> path;                      // Declares path as the vector storing the characters from the file
        int x = 17;                             // Declaring x as 17 so I can use it with recursion below
        char entrance = vec.at(16);             // 'S', the entrance to the maze
        char firstsquare = vec.at(x);           // For the first walkable square next to the entrance

        // Check that the entrance really has 'S'
        if (entrance == 'S')                    
        { 
            path.push_back(entrance);           // Store 'S' into vector 'path'
        }

        // Check if the first path is an alphabetical character and thus walkable
        if (isalpha(firstsquare))               
        {
            path.push_back(firstsquare);        // Store that character into vector 'path'
            isalpha(vec.at(x++));               // Recurse 'isalpha' to the next adajcent square of the maze;
        }                                       // checking next character

        cout << "Path is: ";                    // Printing to screen the first part of our statement

        // This loop to print to the screen all the contents of the vector 'path'.
        for(vector<char>::const_iterator i = path.begin(); i != path.end(); ++i)  // 
        {
        std::cout << *i << ' ';
        }

        cout << endl;
        system ("pause");                       // Keeps the black box that pops up, open, so we can see results.
        return 0;
        }
}

提前致谢！顺便说一句，我是C ++的新手。

Answer 1

由于这看起来像一个学习项目（家庭作业，自学，无论如何），我只会给出提示。

我认为这一行（特别是评论）表明了问题：

isalpha(vec.at(x++)); // Recurse 'isalpha' to the next adajcent square of the maze;

你没有“递归”任何东西而你忽略了isalpha的结果。您只是确定下一个字符是否按字母顺序排列，然后对其执行任何操作，并且只确定该字符。

C ++将文本文件的各个字符打印到屏幕

1 个答案: