我发布这个是因为我无法理解增强教程的工作原理。
我有一个类,其对象是boost multi_index容器的元素。
我需要使用成员函数更新对象的成员变量。我不知道该怎么做。请问你能帮帮我吗。 我准备了一个简单的例子:
#include <string>
#include <iostream>
#include <boost/multi_index_container.hpp>
#include <boost/multi_index/member.hpp>
#include <boost/multi_index/ordered_index.hpp>
#include<vector>
using boost::multi_index::multi_index_container;
using boost::multi_index::ordered_non_unique;
using boost::multi_index::ordered_unique;
using boost::multi_index::indexed_by;
using boost::multi_index::member;
class employee_entry
{
public:
employee_entry( const std::string& first,
const std::string& last,
long id):
first_name_(first),
last_name_(last),
id_(id)
{}
void change(){id_++;}//causing the problem
std::string first_name_;
std::string last_name_;
std::vector<int> mySet;
long id_;
std::vector<int>::iterator mySet_begin() {return mySet.begin(); }
};
typedef multi_index_container<
employee_entry, indexed_by<
ordered_unique<member<employee_entry, std::string, &employee_entry::first_name_> >
, ordered_non_unique<member<employee_entry, std::string, &employee_entry::last_name_> >
, ordered_non_unique<member<employee_entry, long, &employee_entry::id_> >
>
> employee_set;
//employee set.... multi-index
employee_set m_employees;
int main()
{
using boost::multi_index::nth_index;
using boost::multi_index::get;
typedef nth_index<employee_set, 0>::type first_name_view;
first_name_view& fnv = get<0>(m_employees);
fnv.insert(employee_entry("John", "Smith", 110));
fnv.insert(employee_entry("Fudge", "Hunk", 97));
///get employees sorted by id
typedef nth_index<employee_set, 2>::type id_view;
id_view& idv = get <2> (m_employees);
for(id_view::reverse_iterator it = idv.rbegin(), it_end(idv.rend()); it != it_end; ++it)
{
std::cout << it->first_name_ <<" "
<< it->last_name_ << ":"
<< it->id_ << std::endl;
it->change();//calling the troublesome function
}
return 0;
}
生成的错误是:
$c++ dr_function.cpp
dr_function.cpp: In function ‘int main()’:
dr_function.cpp:65:19: error: passing ‘const employee_entry’ as ‘this’ argument of ‘void employee_entry::change()’ discards qualifiers [-fpermissive]
答案 0 :(得分:2)
您发布的解决方案无法正常工作:最多会出现乱码索引,最糟糕的情况是您的应用会崩溃。由于你的最后一个索引取决于employee_entry::id_
,你无法自由地改变它,因为你隐含地破坏了索引顺序。对于这种东西,Boost.MultiIndex提供了更新函数replace
和modify
,正如所讨论的here。在您的特定情况下,您可以按如下方式调用change
成员函数:
idv.modify(idv.iterator_to(*it),boost::bind(&employee_entry::change,_1));
一点解释:idv.iterator_to(*it)
只是将反向迭代器转换为常规迭代器,这是modify
所需要的。对于boost::bind
部分,这将&employee_entry::change
封装到合适的修改函子中。通过这种方式,您可以让Boost.MultiIndex了解id_
即将发生的变化并相应地更新索引。
答案 1 :(得分:0)
long id_
设为mutable
并将void change(){...}
更改为void change()const{...}
#include <string>
#include <iostream>
#include <boost/multi_index_container.hpp>
#include <boost/multi_index/member.hpp>
#include <boost/multi_index/ordered_index.hpp>
#include<vector>
using boost::multi_index::multi_index_container;
using boost::multi_index::ordered_non_unique;
using boost::multi_index::ordered_unique;
using boost::multi_index::indexed_by;
using boost::multi_index::member;
class employee_entry
{
public:
employee_entry( const std::string& first,
const std::string& last,
long id):
first_name_(first),
last_name_(last),
id_(id)
{}
void change() const {id_++;}//causing the problem
std::string first_name_;
std::string last_name_;
std::vector<int> mySet;
mutable long id_;
std::vector<int>::iterator mySet_begin() {return mySet.begin(); }
};
typedef multi_index_container<
employee_entry, indexed_by<
ordered_unique<member<employee_entry, std::string, &employee_entry::first_name_> >
, ordered_non_unique<member<employee_entry, std::string, &employee_entry::last_name_> >
, ordered_non_unique<member<employee_entry, long, &employee_entry::id_> >
>
> employee_set;
//employee set.... multi-index
employee_set m_employees;
int main()
{
using boost::multi_index::nth_index;
using boost::multi_index::get;
typedef nth_index<employee_set, 0>::type first_name_view;
first_name_view& fnv = get<0>(m_employees);
fnv.insert(employee_entry("John", "Smith", 110));
fnv.insert(employee_entry("Fudge", "Hunk", 97));
///get employees sorted by id
typedef nth_index<employee_set, 2>::type id_view;
id_view& idv = get <2> (m_employees);
for(id_view::reverse_iterator it = idv.rbegin(), it_end(idv.rend()); it != it_end; ++it)
{
std::cout << it->first_name_ <<" "
<< it->last_name_ << ":"
<< it->id_ << std::endl;
it->change();//calling the troublesome function
}
return 0;
}