JSON转换

Question

我想知道如何在适当的可解析JSON数组中转换来自服务器的http响应

        try {
            HttpClient httpClient = new DefaultHttpClient();
            HttpPost postRequest = new HttpPost(
                    "http://riffre.com/chatapp/search.php?format=json");
            postRequest.setEntity(new UrlEncodedFormEntity(nameValuePair));
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            responsesrch = httpClient.execute(postRequest, responseHandler);

            Log.v("search response", responsesrch);

这是我的代码，我将一些参数以名称值对的形式发布到服务器 我得到的responseserch的值是

{"users":[{"user":{"city":"gurgaon","username":"zxc","userid":"6","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"tarun","userid":"5","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"vips","userid":"4","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"rah","userid":"3","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"aak","userid":"2","gender":"Male","images":"0"}}]}

这是字符串格式，所以我想知道如何将此字符串转换为json数组，我不知道如何使用输入流和所有这些实体，因此非常感谢任何帮助

Answer 1

请看这个，很简单

http://www.androidhive.info/2012/01/android-json-parsing-tutorial/

将IS转换为String

 try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "n");
            }
            is.close();
            json = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

将String转换为Json对象

try {
            jObj = new JSONObject(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }

从Object获取数组

 // Getting Array of Contacts
    JSONArray  contacts = json.getJSONArray("users");

Answer 2

您可以使用

1. GSON
2. JackSon

如果你想使用json.org中的默认json，那么导入org.json.JSONArray;你可以这样做：

JSONArray jsonArray = new JSONArray(yourJsonString);

请参阅：http://www.vogella.com/articles/AndroidJSON/article.html

Answer 3

这是我工作代码中的一个示例：

   jArray = new JSONArray(result);
   JSONObject json_data = null;
   double[] tempLong = null;
   double[] tempLat = null;
   for (int i = 0; i < jArray.length(); i++) {
       json_data = jArray.getJSONObject(i);
       tempLong = new double[jArray.length()];
       tempLat = new double[jArray.length()];
       tempLong[i] = json_data.getDouble("longtitude");
       tempLat[i] = json_data.getDouble("latitude");
   }

我相信你可以根据自己的需要调整它

Answer 4

如果要将Java对象从/转换为JSON，可以查看：google-gson Java library

Answer 5

使用两行代码

JSONObject jObj = new JSONObject(responsesrch.toString());
JSONArray jArr=jObj.getJSONArray("users");