我正在尝试编写一个简单的程序。它应该从stdin读取链接,并在单独的线程中下载这些链接。我写了下面的代码,但是我遇到了分段错误。谁能想到为什么?
#include <stdio.h>
#include <stdlib.h>
#include <string.h> /* memcpy */
#include <curl/curl.h>
#include <pthread.h>
#define NUMTHREADS 3
struct downloadfile {
char *filename;
FILE *stream;
};
pthread_mutex_t mutex;
/* writedata: custom fwrite for curl writefunction */
static size_t writedata(void *buffer, size_t size, size_t nmemb, void *stream)
{
struct downloadfile *out = (struct downloadfile *) stream;
if (out && !out->stream) {
out->stream = fopen(out->filename, "w");
if (!out->stream)
return -1; /* can't open file to write */
}
return fwrite(buffer, size, nmemb, out->stream);
}
/* getfilename: gets a file's name from a link. */
char *getfilename(const char *link)
{
const char *fnstart = NULL; /* start of filename*/
size_t len = 0; /* length of filename*/
for ( ; *link != '\0'; ++link) {
if (*link == '/') {
fnstart = link + 1;
len = 0;
} else {
++len;
}
}
char *filename = malloc(len + 1);
memcpy(filename, fnstart, len);
filename[len] = '\0';
return filename;
}
/* downloadthread: get a line from stdin, and try to donwload it.*/
void *downloadthread(void *ignored)
{
puts("in a download thread");
CURL *curl;
curl = curl_easy_init();
ssize_t read; /* number of characters read from a line */
if (!curl) { /* couldn't get curl handle */
fputs("Couldn't get curl handle", stderr);
pthread_exit(NULL);
}
for (;;) { /* readline and download loop */
size_t n; /* argument to getline */
char *lineptr = NULL; /* argument to getline */
struct downloadfile ofile;
/* I think I need mutex protect the getline, but I am not sure */
pthread_mutex_lock(&mutex);
read = getline(&lineptr, &n, stdin);
pthread_mutex_unlock(&mutex);
if (read == EOF)
break;
ofile.filename = getfilename(lineptr);
curl_easy_setopt(curl, CURLOPT_URL,lineptr);
/* follow http redirects */
curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION ,1L);
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writedata);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &ofile);
curl_easy_perform(curl);
free(ofile.filename);
free(lineptr);
if (ofile.stream)
fclose(ofile.stream);
}
curl_easy_cleanup(curl);
pthread_exit(NULL);
}
int main()
{
size_t i;
int rc;
pthread_t threads[NUMTHREADS];
curl_global_init(CURL_GLOBAL_ALL);
pthread_mutex_init(&mutex, NULL);
/* fire up threads */
for (i = 0; i < NUMTHREADS; i++) {
rc = pthread_create(&threads[i], NULL, downloadthread, NULL);
if (rc) {
printf("Error, return code from pthread is %d\n", rc);
exit(-1);
}
}
/* join all threads before cleaning up */
for (i = 0; i < NUMTHREADS; i++)
pthread_join(threads[i], NULL);
/* cleanup and exit */
pthread_mutex_destroy(&mutex);
pthread_exit(NULL);
}
编辑:这是gdb的输出。它没有给我很多想法。
[New Thread 0xb61feb40 (LWP 3778)]
[New Thread 0xb57ffb40 (LWP 3779)]
[New Thread 0xb4ffeb40 (LWP 3780)]
[Thread 0xb61feb40 (LWP 3778) exited]
[Thread 0xb57ffb40 (LWP 3779) exited]
[Thread 0xb4ffeb40 (LWP 3780) exited]
Program received signal SIGSEGV, Segmentation fault.
[Switching to Thread 0xb7b25b40 (LWP 3773)]
0xb7e02310 in fwrite () from /lib/libc.so.6
(gdb) bt
#0 0xb7e02310 in fwrite () from /lib/libc.so.6
#1 0xb7f6dd53 in ?? () from /usr/lib/libcurl.so.4
#2 0xb7f85a5e in ?? () from /usr/lib/libcurl.so.4
#3 0xb7f86bb5 in ?? () from /usr/lib/libcurl.so.4
#4 0xb7f87573 in curl_easy_perform () from /usr/lib/libcurl.so.4
#5 0x08048d99 in downloadthread (ignored=0x0) at downloader.c:91
#6 0xb7f47ce8 in start_thread () from /lib/libpthread.so.0
#7 0xb7e874de in clone () from /lib/libc.so.6
答案 0 :(得分:2)
当您声明struct downloadfile ofile
时,其stream
字段将填充垃圾,可能不是0.当ofile
传递给writedata
回调时(由于调用curl_easy_perform
},条件out && !out->stream
因此可能是错误的,并导致writedata
在未打开的流上调用fwrite
。
所以只需将ofile
声明替换为struct downloadfile ofile = { 0, 0 };
。
答案 1 :(得分:0)
for ( ; *link != '\0'; ++link) {
如果路径不包含'/':
for (fnstart=link ; *link != '\0'; ++link) {
(循环下方)if (!fnstart) return BAD_STUFF;
答案 2 :(得分:0)
检查char *getfilename(const char *link)
功能。如果作为参数传递的字符数组不包含任何/
,则const char *fnstart
变量将保持为NULL,您最终将尝试memcpy
至少一个NULL字节。