Array (
[0] => Array (
[event_title] => Registration
[event_id] => 17
[location_id] => 113
)
[1] => Array (
[event_title] => Sunday Collections
[event_id] => 67
[location_id] => 113
)
[2] => Array (
[event_title] => School Tuition
[event_id] => 68
[location_id] => 113
)
)
有人能告诉我如何从此数组中提取event_title
,event_id
和location_id
吗?我想以桌子的形式显示它。
答案 0 :(得分:4)
实际上,数组非常简单。
foreach($array as $item) {
$event_title = $item['event_title'];
$event_id = $item['event_id'];
$location_id = $item['location_id'];
}
答案 1 :(得分:3)
<table><?php
foreach($array as $arr) {
echo '<tr><td>'.
$arr['event_title'].
'</td><td>'.
$arr['event_id'].
'</td><td>'.
$arr['location_id'].
'</td></tr>'.PHP_EOL;
}
?></table>
答案 2 :(得分:3)
要在表格中显示,您可以这样做:
<table>
<tr>
<th>Event Title</th>
<th>Event ID</th>
<th>Location ID</th>
</tr>
<?php foreach($array as $item): ?>
<tr>
<td><?php echo $item['event_title'] ?></td>
<td><?php echo $item['event_id'] ?></td>
<td><?php echo $item['location_id'] ?></td>
</tr>
<?php endforeach; ?>
</table>
答案 3 :(得分:1)
foreach ($arr as $event){
echo $event["event_title"] . "\t" . $event["event_id"] . "\t". $event["location_id"] . "\n";
}
答案 4 :(得分:1)
foreach ($array as $row) {
...
echo "<td>{$row['event_title']}</td>";
...
}