Question

我在wicket中创建一个简单的下拉组件，遵循以下示例：http：//www.mkyong.com/wicket/wicket-select-example/

现在我收到错误：最后一个原因：没有为类定义get方法：class no.polaris.AdressaHomePage expression：2011

有人看到了什么问题吗？（它对于selectedYear的getter没有帮助。）

干杯 Terje Eithun

public class AdressaHomePage extends BasePage {

private String selectedYear = "2011";

public AdressaHomePage(final PageParameters parameters) {

    add(new FeedbackPanel("feedback"));

    Form<?> form = new Form<Void>("form") {

        @Override
        protected void onSubmit() {
            info("Selected year: " + selectedYear);
        }
    };
    add(form);  

    Select<String> yearSelector = new Select<String>("year-selector", new PropertyModel<String>(this, selectedYear));

    yearSelector.add(new SelectOption<String>("year1", new Model<String>("2012")));
    yearSelector.add(new SelectOption<String>("year2", new Model<String>("2011")));
    yearSelector.add(new SelectOption<String>("year3", new Model<String>("2010")));
    yearSelector.add(new SelectOption<String>("year4", new Model<String>("2009")));
    form.add(yearSelector);
}

}

Answer 1

new PropertyModel（this，“selectedYear”）

请注意引号。

wicket select propertymode- -no get method defined

1 个答案: