Question

我在mySQL上运行了一个SQL LIKE查询，它在我的本地开发服务器上运行正常但是在生产服务器上它只适用于单个字母;即如果我输入的单词不超过一个字母，则不会返回任何结果。

任何想法为什么以及如何解决它？

提前谢谢。

/**
* Searches all current vehicle listings for matches to given search string.
* @param string - Search keyword(s). Warning: If search string is empty all current vehicles are returned.
* @return array - Resulting table rows containing vin, imageFile, description, kms, auctioneerName, city, time.
*/

public function searchVehicles($search) { // 
  // Build up initial SQL query. Sub query returns all current vehicles
  $query = "SELECT * FROM (SELECT vehicles.auctionId, vin, imageFile, CONCAT_WS(' ', year, makeName, modelName) as description, kms, auctioneerName, city, time FROM vehicles, models, makes, auctions, auctioneers, locations WHERE time > NOW() AND vehicles.modelId = models.modelId AND models.makeId = makes.makeId AND vehicles.auctionId = auctions.auctionId AND auctions.auctioneerId = auctioneers.auctioneerId AND auctions.locationId = locations.locationId) AS results WHERE";
  $keywords = explode(" ", $search); // Break search into keywords

  // Loop through each keyword in the search to build up SQL query
  $firstLoop = true; // Initial loop flag
  foreach ($keywords as $keyword) {
     if (!$firstLoop) { // Check if this is not the first loop
        $query = $query . " AND"; // Then: Add extension statement to query
     } else {$firstLoop = false;} // Otherwise: Set flag to false

     // Add each keyword search to the query ensuring case insensitivity by converting to uppercase
     $query = $query . " UPPER(description) LIKE UPPER('%" . $this->escape($keyword) . "%')";
  }

  // Add ordering SQL
  $query = $query . " ORDER BY time";

  // Run query and return results (if any)
  return $this->query($query);
}

Answer 1

上面应该在里面。

$query = $query . " UPPER(description) LIKE CONCAT('%',UPPER(" . $this->escape($keyword) . "),'%')";

Answer 2

尝试使用COLLATE

$query = $query . " description COLLATE utf8_general_ci like '" . $this->escape($keyword) . ")%'";

用于不区分大小写的搜索

Answer 3

$query = $query . " UPPER(description) LIKE '%" . strtoupper($this->escape($keyword)) . "%'";

SQL LIKE - 仅处理单个字母

3 个答案: