Question

当我在一个页面中多次调用一个过程时，我很难调用和显示内容。我试图从MYSQL的两个不同SP调用中显示两个单独的记录集。我可以显示第一个呼叫，但第二个呼叫失败。我不确定我做错了什么但也许有人可以帮忙吗？

当我打电话给第二个程序时，我一直收到错误：

Error calling SPCommands out of sync; you can't run this command now

我在Windows上运行

下面的代码...... PHP

// First call to SP
$page = 2;
$section = 1;

include("DatabaseConnection.php"); //general connection - works fine

$sql = 'CALL GetPageContent("'.$page.'", "'.$section.'")';

$result = mysqli_query($conn, $sql) or die('Error calling SP' .mysqli_error($conn));

while($row=mysqli_fetch_assoc($result))
{
   // DO STUFF< REMOVED TO MAKE READING CLEARER
}

mysqli_free_result($result);

//SECOND CALL BELOW


$section = 2; // change parameter for different results

$sql = 'CALL GetPageContent("'.$page.'", "'.$section.'")';

$result = mysqli_query($conn, $sql) or die('Error calling SP' .mysqli_error($conn));


while($row=mysql_fetch_assoc($result))
{
   // DO STUFF< REMOVED TO MAKE READING CLEARER
}

Answer 1

要解决此问题，请记住在每次存储过程调用后调用mysqli对象上的next_result（）函数。见下面的例子：

        <?php
        // New Connection
        $db = new mysqli('localhost','user','pass','database');

        // Check for errors
        if(mysqli_connect_errno()){
         echo mysqli_connect_error();
        }

        // 1st Query
        $result = $db->query("call getUsers()");
        if($result){
             // Cycle through results
            while ($row = $result->fetch_object()){
                $user_arr[] = $row;
            }
            // Free result set
            $result->close();
            $db->next_result();
        }

        // 2nd Query
        $result = $db->query("call getGroups()");
        if($result){
             // Cycle through results
            while ($row = $result->fetch_object()){
                $group_arr[] = $row;
            }
             // Free result set
             $result->close();
             $db->next_result();
        }
        else echo($db->error);

        // Close connection
        $db->close();
        ?>

Answer 2

如果您在单个脚本页面中调用多个过程，则应在调用另一个过程之前调用mysqli_next_result（$ connection_link）。请考虑以下示例代码块：

调用多个存储过程时PHP MYSQL错误

2 个答案: