Question

我的数据库看起来像这样：

[foods]
foods_id, foods_name, groups_id, producers_id

[producers]
producers_id, producers_name

[groups]
groups_id, groups_name

PHP：

<?php
$producers = mysql_query('SELECT p.producers_name,p.producers_id FROM foods as f,producers as p WHERE p.producers_id = f.producers_id AND f.groups_id = 1 GROUP BY p.producers_name');
    //list the producer...
    while($row = mysql_fetch_array($producers, MYSQL_ASSOC)){
        $foods = mysql_query('SELECT foods_id, foods_name FROM foods WHERE producers_id = '.$row['producers_id'].' ORDER BY foods_name ASC');       
        while($row2 = mysql_fetch_array($foods, MYSQL_ASSOC)){
            //list the foods under this producer...
        }
    }
?>

目标：

PRODUCER A
   FOOD A
   FOOD B
   FOOD C
PRODUCER B
   FOOD D
   FOOD E
PRODUCER C
   FOOD F
...

解：

<?php
$res = mysql_query('SELECT f.foods_id, f.foods_name, p.producers_id, p.producers_name FROM foods f, producers p WHERE p.producers_id = f.producers_id AND f.groups_id = '.$_GET['g'].' ORDER BY p.producers_name ASC, f.foods_name ASC');       
$xproducers = array();
while($row = mysql_fetch_array($res , MYSQL_ASSOC)){
    if(!array_key_exists($row['producers_id'],$xproducers)){
        $xproducers[$row['producers_id']] = array('id'=>$row['producers_id'],'name'=>$row['producers_name'],'foods'=>array());
    }
    array_push($xproducers[$row['producers_id']]['foods'],array('id'=>$row['foods_id'],'name'=>$row['foods_name']));
}
?>

这个解决方案对我来说足够快，也许它并不完美，但它的工作做得很好:)我非常感谢大家的帮助！

干杯

Answer 1

我无法理解为什么你先选择，这会得到相同的数据。

$res = mysql_query('SELECT f.foods_id, f.foods_name, p.producers_id, p.producers_name FROM foods f, producers p WHERE p.producers_id = f.producers_id AND f.groups_id = 1');       
    while($row = mysql_fetch_array($res , MYSQL_ASSOC)){
        $producers[$row['producers_id']][$row['foods_id']] = $row;
    }

Answer 2

我会做的

mysql_query('SELECT producers_name, producers_id
FROM producers
WHERE producers_id IN
(SELECT producers_id FROM foods WHERE groups_id = 1)');

这应该更快。

祝你好运！

优化MySQL / PHP查询

2 个答案: