Question

我有这样的链接：

＆LT; a href =“mailto：＆lt;％= @email％＆gt;？subject =回答投诉＆amp; body =＆lt;％= @salutation％＆gt;，”＆gt;答案＆lt; / A＆GT;

如何使用Cucumber / Capybara进行测试？我的意思不仅仅是

我应该看到“答案”

Answer 1

听起来您担心@email链接中的@salutation和mailto:值是正确的。

你可以做这样的事情

page.should have_xpath("//a[contains(@href,email)]"))

Answer 2

我最终选择了Cucumber：

Then /^I should have a mailto link with:$/ do |table| 
  mailto_link = '//a[@href="mailto:' + table.rows_hash['recipient'] + '?subject=' + table.rows_hash['subject'] + '&body=' + table.rows_hash['body'] + ' "]'
  page.should have_xpath(mailto_link)
end

Answer 3

Piotr Brudny添加了URL编码并包含参数顺序无关紧要（我从那里删除了身体，但如果你需要它，你可能会想出来。

Then(/^I should have a mailto link with:$/) do |table|
  mailto_link = ("//a[contains(@href, \"mailto:#{table.rows_hash['recipient']}\")"\
  " and contains(@href, \""+ {
    subject: table.rows_hash['subject']
  }.to_query + '")]').gsub('+', '%20')
  page.should(have_xpath(mailto_link))
end

Answer 4

与接受的答案类似，但略有更新的例子。你可以这样说：

select 
    conname as constraint_name,
    conrelid::regclass as table_name,
    get_col_names(conrelid, conkey) as column_names,
    confrelid::regclass as foreign_table_name,
    get_col_names(confrelid, confkey) as foreing_column_names
from pg_constraint
where contype ='f'
and conrelid = 'comment'::regclass;

  constraint_name  | table_name | column_names | foreign_table_name | foreing_column_names 
-------------------+------------+--------------+--------------------+----------------------
 comment_name_fkey | comment    | name, owner  | cat                | name, owner
(1 row)

如何在Cucumber中测试mailto链接？

4 个答案: