我有2个.jsp页面。
The 1. one contains just a xml structure for applicants:
<% response.setContentType("text/xml") ; %>
<applicant>
<citizenship>GERMANY</citizenship>
<residence>Inc.</residence>
<street>9500 Gilman Drive</street>
<city>La Jolla</city>
<state>USA</state>
<countryTelCode>Vandelay Industries</countryTelCode>
<zipCode>Inc.</zipCode>
<areaCode>9500 Gilman Drive</areaCode>
<telNumber>La Jolla</telNumber>
<major>USA</major>
<awarded>Vandelay Industries</awardeds>
<gpa>Inc.</gpa>
<specialization>9500 Gilman Drive</specialization>
</applicant>
第二个尝试从标签中检索德语并将其打印在以下“...”字段中:
<span id="Citizenship">...</span>
在调用showCustomer()后使用此代码:
<script type="text/javascript">
function showCustomer() {
var xmlHttp;
xmlHttp = new XMLHttpRequest();
if (xmlHttp == null) {
alert("Your browser does not support AJAX!");
return;
}
var url = "getApplicant_xml.jsp";
xmlHttp.onreadystatechange = function() {
if (xmlHttp.readyState == 4) {
var xmlDoc = xmlHttp.responseXML.documentElement;
document.getElementById("Citizenship").innerHTML = xmlDoc.getElementsByTagName("citizenship")[0].childNodes[0].nodeValue;
}
}
xmlHttp.open("GET", url, true);
xmlHttp.send(null);
}
}
</script>
不幸的是它没有打印任何东西.... 如果有人发现我的错误,我会非常感激。
谢谢
答案 0 :(得分:1)
您的问题是xmlHttp.responseXML为null。您需要从xmlHttp.responseText解析一个新的DOM对象。我修改了代码。
<script type="text/javascript">
function showCustomer() {
var xmlHttp;
xmlHttp = new XMLHttpRequest();
if (xmlHttp == null) {
alert("Your browser does not support AJAX!");
return;
}
var url = "getApplicant_xml.jsp";
xmlHttp.onreadystatechange = function() {
if (xmlHttp.readyState == 4) {
var xmlDoc = xmlHttp.responseText;
xmldom = (new DOMParser()).parseFromString(xmlDoc, 'text/xml');
text = xmldom.getElementsByTagName("citizenship")[0];
document.getElementById("Citizenship").innerHTML = text.childNodes[0].nodeValue;
}
};
xmlHttp.open("GET", url, true);
xmlHttp.send(null);
};
</script>