为什么不读这个'if'语句？

Question

在我的代码中，我想要两个答案'对面'和'斜边'，以便有两个不同的结果，但是，每当我测试代码并回答时，'相反'，它会忽略其余的代码然后失败对'斜边'的问题。我是否将其格式化错误/有更简单的方法来执行此操作/等等吗？

from math import *

    def  main():

       #Trignometry Problem

        def answer():
            answer = raw_input()

    while True:

        # Phrase Variables
        phrase1 = ("To begin, we will solve a trigonometry problem using sin.")
        phrase2 = ("Which is known - hypotenuse or opposite?")
        phrase3 = ("Good! Now, we will begin to solve the problem!")
        phrase4 = ("Please press any key to restart the program.")

        print phrase1
        origin=input("What is the origin?")
        print phrase2
        answer = raw_input()
        if answer == ("Hypotenuse.") or ("Hypotenuse") or ("hypotenuse") or ("hyotenuse."):
            hypotenuse=input("What is the hypotenuse?")
            print "So, the problem is " + "sin" + str(origin) + " = " + "x" + "/" + str(hypotenuse) + "?"
            answer = raw_input()
            if answer == ("Yes.") or ("yes") or ("yes.") or ("Yes"):
                print phrase2
            answer = raw_input()
            print phrase4
            answer = raw_input()
            if answer == ("No."):
                break 
        if answer == ("Opposite."):
            opposite=input("What is the opposite?")
            print "So, the problem is " + "sin" + str(origin) +  " = " + str(opposite) + "/" + "x" + "?"
            answer = raw_input()
            if answer == ("Yes.") or ("yes") or ("yes.") or ("Yes"):
                print phrase2
        answer = raw_input()
        print phrase4
        answer = raw_input()
        if answer == ("No."):
            break


    main()

Answer 1

简短回答

您可能想要更改它们：

if answer == ("Hypotenuse") or ("Hypotenuse.") ...

由此：

if answer in ("Hypotenuse", "Hypotenuse.", ...):

说明

表达式：

answer == ("Foo") or ("Bar")

评估如下：

(answer == ("Foo")) or (("Bar"))

"Bar"始终为True。

显然，正如评论中指出的那样，"HYPOTENUSE" in answer.upper()是最佳解决方案。