Question

我目前正在编写一个程序，最终将比较两个目录中的文件并显示每个文件中已更改的函数。但是，在检查目录中的内容是文件还是子目录时，我遇到了问题。现在，当我检查它是否只是一个带-d检查的目录时，它不会捕获任何子目录。我在下面发布了部分代码。

opendir newDir, $newDir;
my @allNewFiles = grep { $_ ne '.' and $_ ne '..'} readdir newDir;
closedir newDir;

opendir oldDir, $oldDir;
my @allOldFiles = grep { $_ ne '.' and $_ ne '..'} readdir oldDir;
closedir oldDir;


foreach (@allNewFiles) {
    if(-d $_) {
        print "$_ is not a file and therefore is not able to be compared\n\n";
    } elsif((File::Compare::compare("$newDir/$_", "$oldDir/$_") == 1)) {
        print "$_ in new directory $newDirName differs from old directory $oldDirName\n\n";
        print OUTPUTFILE "File: $_ has been update. Please check marked functions for differences\n";
        print OUTPUTFILE "\n\n";
        print OUTPUTFILE "+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=\n\n";
    } elsif((File::Compare::compare("$newDir/$_", "$oldDir/$_") < 0)) {
        print "$_ found in new directory $newDirName but not in old directory $oldDirName\n";
        print "Entire file not printed to output file but instead only file name\n";
        print OUTPUTFILE "File: $_ is a new file!\n\n";
        print OUTPUTFILE "+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=\n\n";
    }
 }

foreach (@allOldFiles) {
    if((File::Compare::compare("$newDir/$_", "$oldDir/$_") < 0)) {
        print "$_ found in old directory $oldDirName but not in new directory $newDirName\n\n";
    }
 }

感谢您的帮助！

Answer 1

正如perldoc -f readdir所述：

如果您计划对readdir的返回值进行filetest测试，你最好在前面有问题的目录。否则，因为我们没有chdir那里，它本来会测试错误的文件。

if(-d "$newDir/$_") {

Answer 2

使用Path::Class

use strict;
use warnings;
use Path::Class;


my @allNewFiles = grep { !$_->is_dir } dir("/newDir")->children;

Answer 3

使用递归调用先获取文件列表，然后对它们进行操作。

my $filesA = {};
my $filesB = {};

# you are passing in a ref to filesA or B so no return is needed.
sub getFiles {
  my ($dir, $fileList) = @_;

  foreach my $file (glob("*")) {
    if(-d $file) {
      getFiles($dir . "/" . $file, $fileList); # full relative path saved
    } else {
      $fileList{$dir . "/" . $file}++;         # only files are put into list
    }
  }
}

# get the files list
my $filesA = getFiles($dirA);
my $filesB = getFiles($dirB);

# check them by using the keys from the 2 lists created.

Perl：确定输入是文件还是目录

3 个答案: