我使用Spring的SimpleJdbcInsert类来创建实体 - 例如:
final SimpleJdbcInsert insert = new SimpleJdbcInsert(dataSource).withTableName("abc");
insert.execute(new BeanPropertySqlParameterSource(abc));
是否有一些相当于此课程的更新?例如,假设我们正在处理单列主键,那么类似下面的内容将是一个方便的接口:
final SimpleJdbcUpdate update = new SimpleJdbcUpdate(dataSource).withTableName("abc").withIdColumn("abcId");
update.execute(new BeanPropertySqlParameterSource(abc));
Spring是否提供了开箱即用的功能?
由于 杰
答案 0 :(得分:5)
Spring JIRA中存在一个关于缺少SimpleJdbcUpdate
类:https://jira.springsource.org/browse/SPR-4691的问题。你可能想在那里投票。
答案 1 :(得分:4)
您必须使用JdbcTemplate
请参阅:13.2.1.1 Examples of JdbcTemplate class usage
E.X:
this.jdbcTemplate.update(
"update t_actor set = ? where id = ?",
"Banjo", 5276L);
答案 2 :(得分:4)
对于任何未来的读者 - 我想出了一个使用反射的便利功能;
适用于简单的pojos:
public void dao_update(NamedParameterJdbcTemplate database, String table, Object pojo, String[] keys) {
StringBuilder sqlBuilder = new StringBuilder("UPDATE ");
sqlBuilder.append(table);
sqlBuilder.append(" SET ");
boolean first = true;
for (Field field : pojo.getClass().getDeclaredFields()) {
if (!first) {
sqlBuilder.append(",");
}
first = false;
sqlBuilder.append(field.getName());
sqlBuilder.append(" = :");
sqlBuilder.append(field.getName());
}
first = true;
for (String key : keys) {
if (first) {
sqlBuilder.append(" WHERE ");
} else {
sqlBuilder.append(" AND ");
}
first = false;
sqlBuilder.append(key);
sqlBuilder.append("= :");
sqlBuilder.append(key);
}
database.getJdbcOperations().update(sqlBuilder.toString(), new BeanPropertySqlParameterSource(pojo));
}
使用示例:
dao_update(database, "employee", my_employee, "id");
生成:
UPDATE员工SET id =:id,name =:name,salary =:salary WHERE id =:id
答案 3 :(得分:1)
使用SimpleJdbcTemplate而不是JdbcTemplate可以获得更多类似的效果,并且通过扩展SimpleJdbcDaoSupport,所有数据库操作都可以放在一个DAO类中:
import java.util.List;
import javax.sql.DataSource;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.beans.factory.annotation.Qualifier;
import org.springframework.jdbc.core.BeanPropertyRowMapper;
import org.springframework.jdbc.core.namedparam.BeanPropertySqlParameterSource;
import org.springframework.jdbc.core.namedparam.MapSqlParameterSource;
import org.springframework.jdbc.core.namedparam.SqlParameterSource;
import org.springframework.jdbc.core.simple.SimpleJdbcDaoSupport;
import org.springframework.stereotype.Repository;
@Repository
public class BankDaoImpl extends SimpleJdbcDaoSupport implements BankDao {
@Autowired
public BankDaoImpl(@Qualifier("dataSource") DataSource dataSource) {
setDataSource(dataSource);
}
@Override
public void insert(Bank bank) {
String sql = "INSERT INTO BANK (id, oib, short_name, name, street, town, postal_code, homepage_url, last_change) VALUES (NEXT VALUE FOR bank_seq, :oib, :shortName, :name, :street, :town, :postalCode, :homepageUrl, CURRENT_TIMESTAMP)";
SqlParameterSource parameterSource = new BeanPropertySqlParameterSource(
bank);
getSimpleJdbcTemplate().update(sql, parameterSource);
}
@Override
public void update(Bank bank) {
String sql = "UPDATE BANK SET oib=:oib, short_name=:shortName, name=:name, street=:street, town=:town, postal_code=:postalCode, homepage_url=:homepageUrl, last_change=CURRENT_TIMESTAMP WHERE id=:id";
SqlParameterSource parameterSource = new BeanPropertySqlParameterSource(
bank);
getSimpleJdbcTemplate().update(sql, parameterSource);
}
@Override
public void delete(String id) {
String sql = "DELETE FROM BANK WHERE id=:id";
getSimpleJdbcTemplate().update(sql,
new MapSqlParameterSource("id", id));
}
@Override
public Bank findById(String id) {
String sql = "select b.ID, b.OIB, b.SHORT_NAME, b.NAME, b.STREET, b.TOWN, b.POSTAL_CODE, b.HOMEPAGE_URL, b.LAST_CHANGE, CASE WHEN count(f.id) = 0 THEN 0 ELSE 1 END AS ready " +
"from BANK WHERE b.ID = :id";
return getSimpleJdbcTemplate().queryForObject(sql,
BeanPropertyRowMapper.newInstance(Bank.class),
new MapSqlParameterSource("id", id));
}
}
答案 4 :(得分:0)
执行此操作的简便方法是:(source)
public void setName(int id, String name) {
this.jdbcTemplate.update("update mytable set name = ? where id = ?",
new Object[] {name, new Integer(id)});
}