Question

在我的表格中，我有两个单独的日期字段，X和Y.在字段x中，我的日期为13/08/2008，在字段Y中，我的日期为13/08/2015。

我想知道是否有一种sql方法计算出字段X和Y之间的六个月日期是什么，结果显示在不同的行上？所以，我希望在两个领域得到以下结果：

BEGIN     | END
13-Aug-08 | 13-Feb-09
13-Feb-09 | 13-Aug-09
13-Aug-09 | 15-Feb-10
15-Feb-10 | 13-Aug-10
13-Aug-10 | 14-Feb-11
14-Feb-11 | 15-Aug-11
15-Aug-11 | 13-Feb-12
13-Feb-12 | 13-Aug-12
13-Aug-12 | 13-Feb-13
13-Feb-13 | 13-Aug-13
13-Aug-13 | 13-Feb-14
13-Feb-14 | 13-Aug-14
13-Aug-14 | 13-Feb-15
13-Feb-15 | 13-Aug-15

这可能吗？

由于

Answer 1

您可以尝试这样的事情：

DATE '2006-05-20' + INTERVAL 5 DAY   -> DATE '2006-05-25' 
DATE '2006-05-20' + INTERVAL 5 MONTH -> DATE '2006-10-20' 
DATE '2006-05-20' + INTERVAL 5 YEAR  -> DATE '2011-05-20'

示例1：

CREATE TABLE BEGIN_DATES
(
     BDates DATETIME
); 

INSERT INTO BEGIN_DATES VALUE ('13/08/2008'); 
INSERT INTO BEGIN_DATES VALUE ('13/02/2009');
INSERT INTO BEGIN_DATES VALUE ('13/08/2009');
INSERT INTO BEGIN_DATES VALUE ('15/02/2010');
INSERT INTO BEGIN_DATES VALUE ('13/08/2010');
INSERT INTO BEGIN_DATES VALUE ('14/02/2011');
INSERT INTO BEGIN_DATES VALUE ('15/08/2011');
INSERT INTO BEGIN_DATES VALUE ('13/02/2012');
INSERT INTO BEGIN_DATES VALUE ('13/08/2012');
INSERT INTO BEGIN_DATES VALUE ('13/02/2013');
INSERT INTO BEGIN_DATES VALUE ('13/08/2013');
INSERT INTO BEGIN_DATES VALUE ('13/02/2014');
INSERT INTO BEGIN_DATES VALUE ('13/08/2014');
INSERT INTO BEGIN_DATES VALUE ('13/02/2015');


SELECT BDates AS BEGIN, (BDates + INTERVAL 6 MONTH) AS END
FROM BEGIN_DATES

DROP TABLE BEGIN_DATES

示例2：

BEGIN
SET @date = '2008-08-13';
SET @Edate ='2015-08-13';

WHILE @date <= @Edate DO

SELECT @date AS BEGIN_DATE, CAST(@date AS DATETIME) + INTERVAL 6 MONTH AS END_DATE;  -- ADDDATE(@date,INTERVAL 6 MONTH)

SET @date = CAST(@date AS DATETIME) + INTERVAL 6 MONTH;   -- Or ADDDATE(@date,INTERVAL 6 MONTH)

END WHILE;
END

MySQL查询显示日期之间的时间段

1 个答案: