Question

有一个sqlalchemy对象

class Employee(Base):
    __tablename__ = "employee"
    # Columns
    id = Column(Integer, primary_key=True, autoincrement=True)
    representative_id = Column(Integer, ForeignKey('employee.id'))
    parent_id = Column(Integer, ForeignKey('employee.id'))
    affiliate_id = Column(Integer, ForeignKey('employee.id'))

    # Relatonships
    representative = relationship("Employee", ????)
    parent = relationship("Employee", ????)
    affiliate = relationship("Employee", ????)

如果员工可以拥有0或1个家长，会员和代表，如何以正确的方式配置关系？知道这三个是不同的。 DB - MySQL

Answer 1

我发现自己该怎么做：

class Employee(Base):
    __tablename__ = "employee"
    # Columns
    id = Column(Integer, primary_key=True, autoincrement=True)
    representative_id = Column(Integer, ForeignKey('employee.id'))
    parent_id = Column(Integer, ForeignKey('employee.id'))
    affiliate_id = Column(Integer, ForeignKey('employee.id'))

    # Relatonships
    representative = relationship("Employee", 
                         primaryjoin="Employee.representative_id==Employee.id", 
                         remote_side=[id])
    parent = relationship("Employee",
                         primaryjoin="Employee.parent_id==Employee.id", 
                         remote_side=[id])
    affiliate = relationship("Employee",
                         primaryjoin="Employee.affiliate_id==Employee.id", 
                         remote_side=[id])

SQLAlchemy关系：多个自引用列

1 个答案: