我正在为家庭作业解决2个问题,经过几个小时我刚刚解决了这两个问题,我的最后一个问题是我的两个查询都返回了双倍的数值而不是单个。
这就是我所拥有的:
SELECT SUM(P.AMT_PAID) AS TOTAL_PAID, C.CITATION_ID, C.DATE_ISSUED, SUM(V.FINE_CHARGED) AS TOTAL_CHARGED
FROM PAYMENT P, CITATION C, VIOLATION_CITATION V
WHERE V.CITATION_ID = C.CITATION_ID
AND C.CITATION_ID = P.CITATION_ID
GROUP BY C.CITATION_ID;
和我的另一个:
SELECT C.CITATION_ID, C.DATE_ISSUED, SUM(V.FINE_CHARGED) AS TOTAL_CHARGED, SUM(P.AMT_PAID) AS TOTAL_PAID, SUM(V.FINE_CHARGED) - SUM(P.AMT_PAID) AS TOTAL_OWED
FROM (CITATION C)
LEFT JOIN VIOLATION_CITATION V
ON V.CITATION_ID = C.CITATION_ID
LEFT JOIN PAYMENT P
ON P.CITATION_ID = C.CITATION_ID
GROUP BY C.CITATION_ID
ORDER BY TOTAL_OWED DESC;
我确信我会忽略一些东西。如果其他人可以告诉我我哪里出错了,那将是一个很大的帮助。
答案 0 :(得分:0)
Select Sum(P.Amt_Paid) As Total_Paid, C.Citation_Id
, C.Date_Issued, Sum(V.Fine_Charged) As Total_Charged
From Payment P
Join Citation C
On C.Citation_Id = P.Citation_Id
Join Violation_Citation V
On V.Citation_Id = C.Citation_Id
Group By C.Citation_Id
首先,您应该使用JOIN语法,而不是使用以逗号分隔的表列表。它使阅读更容易,更标准化,并有助于通过忽略过滤条款来防止问题。
其次,总和过大的最可能原因是由于加入VIOLATION_CITATION
表。如果您删除分组依据和具有汇总功能的列,您可能会看到P.AMT_PAID
的每个实例都重复VIOLATION_CITATION
。也许,以下将解决问题:
Select Coalesce(PaidByCitation.TotalAmtPaid,0) As Total_Paid
, C.Citation_Id, C.Date_Issued
, Coalesce(ViolationByCitation.TotalCharged,0) As Total_Charged
, Coalesce(ViolationByCitation.TotalCharged,0)
- Coalesce(PaidByCitation.TotalAmtPaid,0) As Total_Owed
From Citation As C
Left Join (
Select P.Citation_Id, Sum( P.Amt_Paid ) As TotalAmtPaid
From Payment As P
Group By P.Citation_Id
) As PaidByCitation
On PaidByCitation.Citation_Id = C.Citation_Id
Left Join (
Select V.Citation_Id, Sum( V.Find_Charged ) As TotalCharged
From Violation_Citation As V
Group By V.Citation_Id
) As ViolationByCitation
On ViolationByCitation.Citation_Id = C.Citation_Id
使用Coalesce
是为了确保如果左连接不返回给定Citation_ID
值的行,则我们将Null
替换为零。