从这段代码中我可以按预期调用bmwCars.CopyToDataTable（）。
var bmwCars = from car in dataTable.AsEnumerable()
where car.Field<string>("Make").ToLower().Equals("bmw")
select car;
但是当我将一些代码声明改为下面时，我无法调用CopyToDataTable（），为什么？
var bmwCars = from car in dataTable.AsEnumerable()
where car.Field<string>("Make").ToLower().Equals("bmw")
select new
{
Make = car.Field<string>("Make"),
Color = car.Field<string>("Color"),
PetName = car.Field<string>("PetName")
};
答案 0 :(得分：7)
您可以构建自己的CopyToDataTable，其中包含任何类型的IEnumerable（不仅仅是DataRow）并返回一个新的DataTable：
// following would not compile by default
// because input is not an IEnumerable<DataRow> but an anonymous type
var tblResult = bmwCars.CopyToDataTable();
以下是实施（在MSDN的帮助下）：
public class ObjectShredder<T> {
private System.Reflection.FieldInfo[] _fi;
private System.Reflection.PropertyInfo[] _pi;
private System.Collections.Generic.Dictionary<string, int> _ordinalMap;
private System.Type _type;
// ObjectShredder constructor.
public ObjectShredder() {
_type = typeof(T);
_fi = _type.GetFields();
_pi = _type.GetProperties();
_ordinalMap = new Dictionary<string, int>();
}
/// <summary>
/// Loads a DataTable from a sequence of objects.
/// </summary>
/// <param name="source">The sequence of objects to load into the DataTable.</param>
/// <param name="table">The input table. The schema of the table must match that
/// the type T. If the table is null, a new table is created with a schema
/// created from the public properties and fields of the type T.</param>
/// <param name="options">Specifies how values from the source sequence will be applied to
/// existing rows in the table.</param>
/// <returns>A DataTable created from the source sequence.</returns>
public DataTable Shred(IEnumerable<T> source, DataTable table, LoadOption? options) {
// Load the table from the scalar sequence if T is a primitive type.
if (typeof(T).IsPrimitive) {
return ShredPrimitive(source, table, options);
}
// Create a new table if the input table is null.
if (table == null) {
table = new DataTable(typeof(T).Name);
}
// Initialize the ordinal map and extend the table schema based on type T.
table = ExtendTable(table, typeof(T));
// Enumerate the source sequence and load the object values into rows.
table.BeginLoadData();
using (IEnumerator<T> e = source.GetEnumerator()) {
while (e.MoveNext()) {
if (options != null) {
table.LoadDataRow(ShredObject(table, e.Current), (LoadOption)options);
} else {
table.LoadDataRow(ShredObject(table, e.Current), true);
}
}
}
table.EndLoadData();
// Return the table.
return table;
}
public DataTable ShredPrimitive(IEnumerable<T> source, DataTable table, LoadOption? options) {
// Create a new table if the input table is null.
if (table == null) {
table = new DataTable(typeof(T).Name);
}
if (!table.Columns.Contains("Value")) {
table.Columns.Add("Value", typeof(T));
}
// Enumerate the source sequence and load the scalar values into rows.
table.BeginLoadData();
using (IEnumerator<T> e = source.GetEnumerator()) {
Object[] values = new object[table.Columns.Count];
while (e.MoveNext()) {
values[table.Columns["Value"].Ordinal] = e.Current;
if (options != null) {
table.LoadDataRow(values, (LoadOption)options);
} else {
table.LoadDataRow(values, true);
}
}
}
table.EndLoadData();
// Return the table.
return table;
}
public object[] ShredObject(DataTable table, T instance) {
FieldInfo[] fi = _fi;
PropertyInfo[] pi = _pi;
if (instance.GetType() != typeof(T)) {
// If the instance is derived from T, extend the table schema
// and get the properties and fields.
ExtendTable(table, instance.GetType());
fi = instance.GetType().GetFields();
pi = instance.GetType().GetProperties();
}
// Add the property and field values of the instance to an array.
Object[] values = new object[table.Columns.Count];
foreach (FieldInfo f in fi) {
values[_ordinalMap[f.Name]] = f.GetValue(instance);
}
foreach (PropertyInfo p in pi) {
values[_ordinalMap[p.Name]] = p.GetValue(instance, null);
}
// Return the property and field values of the instance.
return values;
}
public DataTable ExtendTable(DataTable table, Type type) {
// Extend the table schema if the input table was null or if the value
// in the sequence is derived from type T.
foreach (FieldInfo f in type.GetFields()) {
if (!_ordinalMap.ContainsKey(f.Name)) {
// Add the field as a column in the table if it doesn't exist
// already.
DataColumn dc = table.Columns.Contains(f.Name) ? table.Columns[f.Name]
: table.Columns.Add(f.Name, f.FieldType);
// Add the field to the ordinal map.
_ordinalMap.Add(f.Name, dc.Ordinal);
}
}
foreach (PropertyInfo p in type.GetProperties()) {
if (!_ordinalMap.ContainsKey(p.Name)) {
// Add the property as a column in the table if it doesn't exist
// already.
DataColumn dc = table.Columns.Contains(p.Name) ? table.Columns[p.Name]
: table.Columns.Add(p.Name, p.PropertyType);
// Add the property to the ordinal map.
_ordinalMap.Add(p.Name, dc.Ordinal);
}
}
// Return the table.
return table;
}
}
现在您可以添加以下扩展程序：
public static class CustomLINQtoDataSetMethods {
public static DataTable CopyToDataTable<T>(this IEnumerable<T> source) {
return new ObjectShredder<T>().Shred(source, null, null);
}
public static DataTable CopyToDataTable<T>(this IEnumerable<T> source,
DataTable table, LoadOption? options) {
return new ObjectShredder<T>().Shred(source, table, options);
}
}
瞧！现在CopyToDataTable适用于任何类型的IEnumerable<T>：）
答案 1 :(得分：5)
根据您对Field<T>的使用，dataTable中的对象（我假设其类型为Car）继承DataRow。这是调用CopyToDataTable扩展方法所必需的。但是，如上所述，您将返回匿名类型的枚举，该枚举无法继承DataRow。
所以，可能是你的
select new
应该是
select new Car
这样您就可以返回IEnumerable<Car>而不是IEnumerable<>的匿名类型。
根据Car类的确切结构，可能需要进行一些次要的语法更改。如果Car包含公共属性，Make，Color和PetName，那么它将按照我的建议运行。相反，如果Car具有方法签名大约等于
public Car(string make, string color, string petName)
然后你必须将LINQ语句改为
var bmwCars = from car in dataTable.AsEnumerable()
where car.Field<string>("Make").ToLower().Equals.("bmw")
select new Car(
car.Field<string>("Make"),
car.Field<string>("Color"),
car.Field<string>("PetName")
);
答案 2 :(得分：3)
因为你要返回一个新的匿名类型，而不是汽车对象本身。