没有定义名为'transactionManager'的bean

时间:2012-05-23 12:12:12

标签: java spring hibernate java-ee

我已经配置了两个持久性单元,实体管理器设置如下:

<bean id="liveEntityManagerFactory" 
          class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
          p:dataSource-ref="LiveDataSource">          

          <property name="persistenceUnitName" value="LivePersistenceUnit" />
    </bean>

    <bean id="archiveEntityManagerFactory" 
          class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
          p:dataSource-ref="ArchiveDataSource">          

          <property name="persistenceUnitName" value="ArchivePersistenceUnit" />
    </bean>

然后我将事务管理器配置为

 <bean id="LiveTransactionManager"
          class="org.springframework.orm.jpa.JpaTransactionManager"
          p:entityManagerFactory-ref="liveEntityManagerFactory"/>

    <bean id="ArchiveTransactionManager"
          class="org.springframework.orm.jpa.JpaTransactionManager"
          p:entityManagerFactory-ref="archiveEntityManagerFactory"/>  

我最初只配置了一个,它被称为“transactionManager”。 Addint一个额外的持久单元似乎会产生错误。 有一点我不明白,如果我配置了两个持久性单元(每个用于一个单独的数据库),我是否还需要为每个数据源配置一个单独的实体管理器和一个事务管理器?

我得到的错误如下所示:(我搜索了所有文件,我找不到任何有“transactionManager”参考的地方)

org.springframework.ws.soap.client.SoapFaultClientException: No bean named 'transactionManager' is defined
    at org.springframework.ws.soap.client.core.SoapFaultMessageResolver.resolveFault(SoapFaultMessageResolver.java:37)
    at org.springframework.ws.client.core.WebServiceTemplate.handleFault(WebServiceTemplate.java:774)
    at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:600)
    at org.springframework.ws.client.core.WebServiceTemplate.sendAndReceive(WebServiceTemplate.java:537)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:384)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:378)
    at org.springframework.ws.client.core.WebServiceTemplate.marshalSendAndReceive(WebServiceTemplate.java:370)
    at com.ws.client.SoapTest.testFail(SoapTest.java:140)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
    at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
    at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
    at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
    at org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate(RunBeforeTestMethodCallbacks.java:74)
    at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
    at org.springframework.test.context.junit4.statements.RunAfterTestMethodCallbacks.evaluate(RunAfterTestMethodCallbacks.java:83)
    at org.springframework.test.context.junit4.statements.SpringRepeat.evaluate(SpringRepeat.java:72)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:231)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:46)
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:180)
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:41)
    at org.junit.runners.ParentRunner$1.evaluate(ParentRunner.java:173)
    at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
    at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61)
    at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
    at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:71)
    at org.junit.runners.ParentRunner.run(ParentRunner.java:220)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:174)
    at org.apache.maven.surefire.junit4.JUnit4TestSet.execute(JUnit4TestSet.java:53)
    at org.apache.maven.surefire.junit4.JUnit4Provider.executeTestSet(JUnit4Provider.java:123)
    at org.apache.maven.surefire.junit4.JUnit4Provider.invoke(JUnit4Provider.java:104)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at org.apache.maven.surefire.util.ReflectionUtils.invokeMethodWithArray(ReflectionUtils.java:164)
    at org.apache.maven.surefire.booter.ProviderFactory$ProviderProxy.invoke(ProviderFactory.java:110)
    at org.apache.maven.surefire.booter.SurefireStarter.invokeProvider(SurefireStarter.java:175)
    at org.apache.maven.surefire.booter.SurefireStarter.runSuitesInProcessWhenForked(SurefireStarter.java:107)
    at org.apache.maven.surefire.booter.ForkedBooter.main(ForkedBooter.java:68)

我正在使用Spring和Jpa / Hibernate。

由于

4 个答案:

答案 0 :(得分:26)

transaction-manager属性的默认值是transaction-manager。在您的情况下,您应该按照以下方法或服务指定要使用的事务管理器:

@Service
@Transactional(value="LiveTransactionManager") 
class someClass...

@Transactional(value="ArchiveTransactionManager") 
public void someMethod

答案 1 :(得分:8)

实际上, 是一种在Spring Data JPA中使用命名的TransactionManager的方法。这对我有用:

<bean id="myTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="myEntityManagerFactory" />
</bean>
<tx:annotation-driven transaction-manager="myTransactionManager"/>

<jpa:repositories base-package="com.xxx.yyy" entity-manager-factory-ref="myEntityManagerFactory" transaction-manager-ref="myTransactionManager">
</jpa:repositories>

答案 2 :(得分:1)

我使用Java配置,并指定 transactionManagerRef 对我来说是解决方案:

@Configuration
@EnableTransactionManagement
@EnableJpaRepositories(
    entityManagerFactoryRef = "myCustomEntityManagerFactory",
    basePackages = {"ua.demitt.other.path.to.repos"},
    transactionManagerRef = "myCustomTransactionManager" )

答案 3 :(得分:0)

在@Configuration文件中,如果这是您的数据源:

@Bean(name = "dataSource")
public DataSource getDataSource() {
    return DataSourceBuilder
            .create()
            .username(username)
            .password(password)
            .url(url)
            .build();
}

这将是您的事务管理器bean:

@Bean(name = "DataSourceTransactionManager")
public DataSourceTransactionManager getDataSourceTransactionManager() {
    return new DataSourceTransactionManager(getDataSource());
}

然后注释您要进行事务处理的服务方法:

@Transactional(transactionManager = "DataSourceTransactionManager", timeout = 60, rollbackFor = { Exception.class})
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