我目前正在处理办公室加载项,我需要显示一个显示进度的通知对话框,我正在使用Philipp Sumi's wpf-notifyicon。
我需要从一个单独的线程中显示notifyicon,因为我有很多代码已经在主线程上执行,这导致wpf-notifyicon阻塞并等待,因为windows消息队列中的消息没有被处理。
我知道我应该在一个单独的线程上执行这个耗时的代码,并从主线程显示notifyicon并相应地更新它,但遗憾的是这不是一个替代方案,因为整个解决方案都是单线程的。
示例:
private FancyPopup fancyPopup;
private void button1_Click(object sender, EventArgs e)
{
notifyIcon = new TaskbarIcon();
notifyIcon.Icon = Resources.Led;
fancyPopup = new FancyPopup();
Thread showThread = new Thread(delegate()
{
notifyIcon.ShowCustomBalloon(fancyPopup, System.Windows.Controls.Primitives.PopupAnimation.Fade, null);
});
showThread.Start();
}
private void button2_Click(object sender, EventArgs e)
{
fancyPopup.TextB.Text = "Doing something...";
//Keep the main thread busy.
Thread.Sleep(5000);
fancyPopup.TextB.Text = "Done doing something...";
}
更新 通过这个更新的代码,我已经能够进一步发展:
我正在新线程上创建TaskbarIcon对象,并使用Application.Run处理该线程上的应用程序消息循环......
private FancyPopup fancyPopup;
private void button1_Click(object sender, EventArgs e)
{
Thread showThread = new Thread(delegate()
{
notifyIcon = new TaskbarIcon();
notifyIcon.Icon = Resources.Led;
fancyPopup = new FancyPopup();
notifyIcon.ShowCustomBalloon(fancyPopup, System.Windows.Controls.Primitives.PopupAnimation.Fade, null);
System.Windows.Forms.Application.Run();
});
showThread.SetApartmentState(ApartmentState.STA);
showThread.Start();
}
private void button2_Click(object sender, EventArgs e)
{
fancyPopup.Dispatcher.Invoke(new Action(delegate
{
fancyPopup.TextB.Text = "Doing something...";
}));
//Keep the main thread busy.
Thread.Sleep(5000);
fancyPopup.Dispatcher.Invoke(new Action(delegate
{
fancyPopup.TextB.Text = "Done doing something...";
}));
}
答案 0 :(得分:2)
我已经解决了我的问题,我不得不在单独的STA线程上初始化 notifyIcon 并使用 Application.Run 来开始在该线程上抽取窗口消息。
var myThread = new Thread(delegate()
{
notifyIcon = new NotifyIcon();
Application.Run();
});
myThread.SetApartmentState(ApartmentState.STA);
myThread.Start();
然后我只需要调用我的通知对话框的UI。