我有每日数据(4011天)和指标(1个工作日,2个周末)。我想找到每周最大值与相应的指标。例如(比方说)数据是:
mydat <- matrix(c(0.027,0.034,0.019,0.021,0.026,0.024,0.058,0.026,0.064,
0.066,0.026,0.101,0.069,0.054,rep(2,2),rep(1,5),rep(2,2),rep(1,5)), ncol=2)
我尝试使用以下代码。我设法获得最大序列(在这种情况下,每周最大值),但我不想要指标中的最大序列。这是代码
week.max <- function(vec){
if(length(vec[is.na(vec)]) == 7){
return(NA)
}
else{
return(max(vec, na.rm = T))
}
}
max.week.dat <- apply(mydat, 2, function(x) tapply(x, rep(1:(length(x)/7),
each=7, len=length(x)), week.max))
和结果
matrix(c(0.058,0.101,2,2),ncol=2)
我希望输出如下:
matrix(c(0.058,0.101,1,1),ncol=2)
非常感谢提前。
答案 0 :(得分:1)
这是数据(第三周额外的一天)
mydat <- data.frame(value = c(0.027,0.034,0.019,0.021,0.026,0.024,0.058,0.026,0.064,
0.066,0.026,0.101,0.069,0.054,0.95), ind = c(rep(2,2),rep(1,5),rep(2,2),rep(1,5),2))
你的功能
week.max <- function(vec){
if(length(vec[is.na(vec)]) == 7){
return(NA)
}
else{
return(max(vec, na.rm = T))
}
}
添加周信息
mydat$week <- c(rep(1:2,each=7),3)
使用与here
相同的解决方案library(plyr)
ddply(mydat, .(week), subset, subset = value==week.max(value), select = -week)