是否有任何方法可以为所有C<>?提供单个静态字段值?

时间:2012-05-22 20:07:46

标签: c# generics

我想编写一个C类,使其具有一个静态字段,该字段初始化一次并且对于所有C<>保持不变。

这可能吗?

以下是我正在使用的示例:

void Main()
{
    Console.WriteLine (C<A>.Value);
    Console.WriteLine (C<B>.Value);
    Console.WriteLine (C<A>.Value2);
    Console.WriteLine (C<B>.Value2);
}

class C<T>
{
    static O O = new O();
    public static string Value { get { return "value of C<T> where T : " + typeof(T).Name; } }
    public static string Value2 { get { return O.ToString() ?? "value of C<T> where T : " + typeof(T).Name; } }
}

class O
{
    Guid guid;
    public O()
    {
        this.guid = Guid.NewGuid();
        Console.WriteLine ("O created {0}", this.guid);
    }
    public override string ToString()
    {
        return this.guid.ToString();
    }
}

class A
{
}

class B
{
}

输出:

value of C<T> where T : A
value of C<T> where T : B
O created 05e6885b-2aa3-4d0d-aec1-fefbe5294f07
05e6885b-2aa3-4d0d-aec1-fefbe5294f07
O created 864554bf-6980-4a0f-9b63-4c0affa21222
864554bf-6980-4a0f-9b63-4c0affa21222

1 个答案:

答案 0 :(得分:5)

当然,从BaseC派生C并在那里声明静态字段,如下所示:

class BaseC
{
    protected static O = new O();
}

class C<T>: BaseC ...