JPA Transaction未提交给DB

时间:2012-05-22 18:36:53

标签: spring hibernate jpa transactions

我正在开发一个小型的Spring-Hibernate-Mysql测试项目,由于某种原因,我的交易没有被提交给数据库。

在我的应用程序环境中,我得到了:

<!-- JTA -->

<bean id="txManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="entityManagerFactory" />

</bean>

<tx:annotation-driven transaction-manager="txManager" />

<!-- JPA -->

<jee:jndi-lookup id="entityManagerFactory" jndi-name="persistence/myPU" />

<!-- In order to enable EntityManager injection -->
<bean
    class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor">
    <property name="persistenceUnits">
        <map>
            <entry key="myPU" value="persistence/myPU" />
        </map>
    </property>
</bean>

我的persistence.xml:

<persistence-unit name="myPU" transaction-type="JTA">
    <provider>org.hibernate.ejb.HibernatePersistence</provider>
    <jta-data-source>jdbc/mysqlResource</jta-data-source>
    <properties>
        <property name="hibernate.connection.shutdown" value="true" />
        <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect"></property>
        <property name="hibernate.show_sql" value="true" />
    </properties>
</persistence-unit>

我在db中创建了一个名为'persons'的简单表:

CREATE TABLE persons(
id VARCHAR(255) PRIMARY KEY,
version int, 
full_name VARCHAR(255),
person_id VARCHAR(255),
email VARCHAR(255));

创建实体相应的实体和Dao:

@Entity
@Table(name = "persons")
public class Person implements Serializable {

private static final long serialVersionUID = 4349832844316517922L;

/*--- Members ---*/

/**
 * Hibernate genetared UUID
 */
@Id
@GeneratedValue(generator = "system-uuid")
@GenericGenerator(name = "system-uuid", strategy = "uuid")
private String id;

@Version
private int version;

@Column(name = "full_name")
private String fullName;

@Column(name = "person_id")
private String personId;

@Column(name = "email")
private String eMail;

/*--- Constructor ---*/

public Person() {
}

/*--- Overridden Methods ---*/

@Override
public boolean equals(Object obj) {

    if ((obj == null) || !(obj instanceof Person)) {
        return false;
    }

    // reference comparison
    if (obj == this) {
        return true;
    }

    final Person other = (Person) obj;

    return new EqualsBuilder().append(getPersonId(), other.getPersonId())
            .append(geteMail(), other.geteMail())
            .append(getFullName(), other.getFullName()).isEquals();
}

/**
 * The unique hash code based on the clients' id and citizenship
 * 
 * {@inheritDoc}
 */
@Override
public int hashCode() {

    return new HashCodeBuilder().append(geteMail()).append(this.geteMail())
            .append(this.getFullName()).toHashCode();
}

/*--- Getters & Setters ---*/

public String getId() {
    return id;
}

public void setId(String id) {
    this.id = id;
}

public int getVersion() {
    return version;
}

public void setVersion(int version) {
    this.version = version;
}

public String getFullName() {
    return fullName;
}

public void setFullName(String fullName) {
    this.fullName = fullName;
}

public String getPersonId() {
    return personId;
}

public void setPersonId(String personId) {
    this.personId = personId;
}

public String geteMail() {
    return eMail;
}

public void seteMail(String eMail) {
    this.eMail = eMail;
}

}

道:

@Repository
public class PersonJpaDao extends BasicJpaDao<Person> implements IPersonDao {

public PersonJpaDao() {
    super(Person.class);
}

}

这里是BasicJpaDao:

public class BasicJpaDao<T> implements IBasicDao<T> {

/* --- Members --- */

/** The JPA utility to work with the persistence layer. */
@PersistenceContext
protected EntityManager entityManager;

/** The type of the entity to which this DAO offers access. */
protected Class<T> entityClass;

/* --- Constructors --- */

/**
 * Default constructor.
 * 
 * @param entityClass
 *            The type of the entity to which this DAO offers access.
 */
public BasicJpaDao(Class<T> entityClass) {
    super();
    this.entityClass = entityClass;
}

/* --- Public methods --- */

/**
 * {@inheritDoc}
 */
@Override
public void create(T entity) {
    getEntityManager().persist(entity);
}

/**
 * {@inheritDoc}
 */
@Override
public T read(Object primaryKey) {
    return getEntityManager().find(getEntityClass(), primaryKey);
}

/**
 * {@inheritDoc}
 */
@Override
public T update(T entity) {
    return getEntityManager().merge(entity);
}

/**
 * {@inheritDoc}
 */
@Override
public void delete(T entity) {
    getEntityManager().remove(entity);
}

/**
 * {@inheritDoc}
 */
@Override
public void flush() {
    getEntityManager().flush();
}

/* --- Getters/Setters --- */

/**
 * @return The JPA utility to work with the persistence layer.
 */
public EntityManager getEntityManager() {
    return this.entityManager;
}

/**
 * @param entityManager
 *            The JPA utility to work with the persistence layer.
 */
public void setEntityManager(EntityManager entityManager) {
    this.entityManager = entityManager;
}

/**
 * @return The type of the entity to which this DAO offers access.
 */
public Class<T> getEntityClass() {
    return entityClass;
}

/**
 * @param entityClass
 *            The type of the entity to which this DAO offers access.
 */
public void setEntityClass(Class<T> entityClass) {
    this.entityClass = entityClass;
}

Soo ..基本上它可以工作,但没有任何东西可以提交,我的意思是,如果我运行

@Transactional(propagation = Propagation.REQUIRED)
private void crearePerson() {
    Person p1 = myDao.read("12345");
    p1.setFullName("kiko too");
    myDao.update(p1);
}

我可以看到(在调试中)p1从数据库返回,但更新永远不会发生。 我能找到的唯一接近的是:

JPA - transactions not being committed

我尝试添加

<property name="hibernate.connection.shutdown" value="true" />

到我的persistence.xml后面这个线程,但它没有帮助。 我还在我的连接池(在我的应用程序服务器gui中)添加了一个名为connection.shutdown的属性,其值为true,但它也没有帮助。

更新 由于我正在使用JTA,我认为我的事务管理器配置错误。当我使用org.springframework.orm.jpa.JpaTransactionManager时,我应该使用org.springframework.transaction.jta.JtaTransactionManager。 所以我改变了我的应用程序上下文,现在我已经:

<bean id="txManager"
    class="org.springframework.transaction.jta.JtaTransactionManager" />

<tx:annotation-driven transaction-manager="txManager" />

不幸的是,我仍然遇到同样的问题:( 在我的控制台中,我可以看到hibernate查询如下()我已经改变了一些原始实体字段,但这并不重要):

INFO:Hibernate:选择user0_.id为id0_0_,user0_.email为email0_0_,user0_.full_name为full3_0_0_,user0_.password为password0_0_,user0_.update_by_email为update5_0_0_,user0_.user_name为user6_0_0_,user0_.version为version0_0_ from用户user0_ where user0_.id =?

有什么想法吗?

提前致谢, 瑜珈

3 个答案:

答案 0 :(得分:3)

它可能无法正常工作的原因是因为您在私有方法上使用@Transactional@Transactional对非公共方法没有影响,因为代理生成器会忽略它们。来自Spring Documentation

  

方法可见性和@Transactional

     

使用代理时,应该应用@Transactional注释   仅限具有公众可见度的方法。如果你做注释保护,   使用@Transactional注释的私有或包可见方法,   没有引发错误,但带注释的方法没有出现错误   配置的事务设置。考虑使用AspectJ(参见   如果你需要注释非公开方法。

答案 1 :(得分:1)

将“@Transactional”添加到create()方法中。

编辑:最好将@Transactional放在服务层而不是dao层只是fyi

答案 2 :(得分:1)

我遇到了类似的问题,对我而言,解决方案来自以下方面:

在PersistenceXML中:

<property name="hibernate.transaction.manager_lookup_class"
value="org.hibernate.transaction.JBossTransactionManagerLookup">

Spring文件:

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="persistenceUnitName" value="nameOfUnitInPersistenceXml" />
</bean>

<bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager">
    <property name="transactionManagerName" value="java:/TransactionManager" />
</bean>

Java类(命名持久化上下文)

private EntityManager em;

@PersistenceContext(name="nameOfUnitInPersistenceXml")
public void setEntityManager(EntityManager em) {
    this.em = em;
}