Question

我想使用PyLZMA从存档中提取文件（例如test.7z）并将其解压缩到同一目录。

我是Python的新手，不知道如何开始。我做了一些谷歌搜索，发现some examples和docs，但我不明白它们是如何工作的。

有人可以发布我想要做的基本代码，以便我可以开始工作并理解吗？

Answer 1

这是一个用于处理基本功能的Python类。我用它来做我自己的工作：

import py7zlib
class SevenZFile(object):
    @classmethod
    def is_7zfile(cls, filepath):
        '''
        Class method: determine if file path points to a valid 7z archive.
        '''
        is7z = False
        fp = None
        try:
            fp = open(filepath, 'rb')
            archive = py7zlib.Archive7z(fp)
            n = len(archive.getnames())
            is7z = True
        finally:
            if fp:
                fp.close()
        return is7z

    def __init__(self, filepath):
        fp = open(filepath, 'rb')
        self.archive = py7zlib.Archive7z(fp)

    def extractall(self, path):
        for name in self.archive.getnames():
            outfilename = os.path.join(path, name)
            outdir = os.path.dirname(outfilename)
            if not os.path.exists(outdir):
                os.makedirs(outdir)
            outfile = open(outfilename, 'wb')
            outfile.write(self.archive.getmember(name).read())
            outfile.close()

Answer 2

以下是我在http://www.linuxplanet.org/blogs/?cat=3845

找到的两个代码段

# Compress the input file (as a stream) to a file (as a stream)
i = open(source_file, 'rb')
o = open(compressed_file, 'wb')
i.seek(0)
s = pylzma.compressfile(i)
while True:
    tmp = s.read(1)
    if not tmp: break
    o.write(tmp)
o.close()
i.close()

# Decomrpess the file (as a stream) to a file (as a stream)
i = open(compressed_file, 'rb')
o = open(decompressed_file, 'wb')
s = pylzma.decompressobj()
while True:
    tmp = i.read(1)
    if not tmp: break
    o.write(s.decompress(tmp))
o.close()
i.close()

如何使用PyLZMA的示例

2 个答案: