jQuery变量包含“和”

Question

是否可以用'替换postbody变量中的'而不实际编辑postbody变量内容

var postbody = '<div class="postbody">this is tom's and bill's post</div>';
var postid = $('#post-content');
postid.append(postbody);​

http://jsfiddle.net/3nVrZ/

Answer 1

创建一个元素并设置其文本，然后您不必对其进行编码：

var post = $('<div/>', { 'class': 'postbody' });
post.text("this is tom's and bill's post");
$('#post-content').append(post);​

Answer 2

您可以使用

var postbody = '<div class="postbody">this is tom\'s and bill\'s post</div>';

或

var postbody = "<div class=\"postbody\">this is tom's and bill's post</div>";

Answer 3

如果你真的想要替换字符串中的内容，只需使用replace（）：

var postbody = "<div class=\"postbody\">this is tom's and bill's post</div>";
postbody = postbody.replace(/\'/g, "&#39;");

Answer 4

尝试使用此

var postbody = "<div class='postbody'>this is tom's and bill's post</div>";
var postid = $('#post-content');
postid.append(postbody);​

http://jsfiddle.net/ipsjolly/3nVrZ/1/