我正在使用此查询:
SELECT district, id
FROM adverts ls
GROUP BY district, id
HAVING (
SELECT count( * )
FROM adverts
WHERE district = ls.district
AND id > ls.id
) <5
ORDER BY district, id DESC ;
LIMIT 0 , 30
花了大约35秒。以下是解释:
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY ls range NULL i_id 5 NULL 16166 Using index for group-by; Using temporary; Using f...
2 DEPENDENT SUBQUERY ilan_genel ref PRIMARY,i_id,i_ozellik_id,i_tip_fiyat,i_tip_id,i_d... i_durum_id 2 func 25 Using where; Using index
有没有办法让它更快?
答案 0 :(得分:1)
试试这个:
SELECT district, id, COUNT(b.district)
FROM adverts a INNER JOIN adverts b
ON a.district = b.district
WHERE b.id > a.id
GROUP BY district, id
HAVING COUNT(b.district) < 5
ORDER BY district, id DESC
根据定义,Joins
比subqueries
更快。