这是我的更新查询。
UPDATE sugarcrm.qb_salesorders_leads_c, sugarcrm.qb_salesorders
SET sugarcrm.qb_salesorders_leads_c.qb_salesorders_leadsleads_ida = sugarcrm.qb_salesorders.memo, sugarcrm.qb_salesorders_leads_c.qb_salesorders_leadsqb_salesorders_idb = sugarcrm.qb_salesorders.id
WHERE sugarcrm.qb_salesorders.id = sugarcrm.qb_salesorders_leads_c.qb_salesorders_leadsqb_salesorders_idb
当我运行它时,它会给我一个受影响的行0。
这是我的select语句,它使用WHERE语句中的相同信息。
SELECT * from qb_salesorders_leads_c, sugarcrm.qb_salesorders
WHERE sugarcrm.qb_salesorders_leads_c.qb_salesorders_leadsqb_salesorders_idb = sugarcrm.qb_salesorders.id
这将返回354行,这是我期望在更新查询上更新的内容。我错过了什么请帮忙!
答案 0 :(得分:1)
将隐式连接转换为显式连接:
UPDATE sugarcrm.qb_salesorders_leads_c leads
INNER JOIN sugarcrm.qb_salesorders orders
ON orders.id = leads.qb_salesorders_leadsqb_salesorders_idb
SET leads.qb_salesorders_leadsleads_ida = orders.memo,
leads.qb_salesorders_leadsqb_salesorders_idb = orders.id
正如您所看到的,我还使用了别名来使SQL紧凑且易读。
答案 1 :(得分:0)
要使用连接进行更新,您必须使用显式连接语法:
UPDATE sugarcrm.qb_salesorders_leads_c
INNER JOIN sugarcrm.qb_salesorders
ON qb_salesorders_leadsqb_salesorders_idb.id
= sugarcrm.qb_salesorders_leads_c.qb_salesorders_leadsqb_salesorders_idb
SET sugarcrm.qb_salesorders_leads_c.qb_salesorders_leadsleads_ida
= qb_salesorders_leadsqb_salesorders_idb.memo
, sugarcrm.qb_salesorders_leads_c.qb_salesorders_leadsqb_salesorders_idb
= sugarcrm.qb_salesorders.id