MySQL COUNT天

Question

我希望在图表中获取访问我网页10天的用户的价值。我需要COUNT（）过去十天的所有值。

最佳布局是

Day|COUNT(ip)

1 - 10
2 - 12
3 - 52
......

我希望你理解我的意思。 MySQL可以直接执行此操作还是需要我在PHP中以10个单独的查询执行此操作？

此致 Moritz的

使用Tablestructure更新：

    Id (Auto Increment)|Time (Unix Timestamp)|Ip|Referer

Answer 1

这将为您提供具有实际日期值的结果：

SELECT
    COUNT(DISTINCT ip),
    FROM_UNIXTIME(Time, '%m/%d/%Y') AS Day
FROM
    tbl
WHERE
    Time >= UNIX_TIMESTAMP(DATE_ADD(CURDATE(), INTERVAL -10 DAY))
GROUP BY
    FROM_UNIXTIME(Time, '%m/%d/%Y')

Answer 2

这应该可以快速运行

SELECT COUNT(ip) ipcount,dt FROM
(
    SELECT ip,DATE(FROM_UNIXTIME(`Time`)) as dt FROM mytable
    WHERE `Time` > TO_UNIXTIME(NOW() - INTERVAL 10 DAY)
) A GROUP BY dt;

确保您在Time

上有索引

ALTER TABLE mytable ADD INDEX TimeIndex (`Time`);

Answer 3

试试这个：

SELECT CAST(DATE(FROM_UNIXTIME(`Time`)) AS CHAR) as dateoftime, COUNT(Ip) as cnt
FROM tablename
WHERE DATE(FROM_UNIXTIME(`Time`)) > DATE_SUB(current_timestamp, INTERVAL 10 DAY)
GROUP BY CAST(DATE(FROM_UNIXTIME(`Time`)) AS CHAR)