我有一个Visual Studio 2008 C ++ 03应用程序,我想基于二维数组初始化一个std :: vector。
例如:
#define DATA_SIZE 6
struct Data
{
UINT a;
BYTE b;
BYTE c;
BYTE d;
Data()
: /* initialize all members to 0*/
{
};
explicit Data( const BYTE data[ DATA_SIZE ] )
: a( data[ 0 ] << 16 | data[ 1 ] << 8 | data[ 2 ] ),
b( data[ 3 ] ),
c( data[ 4 ] ),
d( data[ 5 ] )
{
};
};
inline bool operator==( const Data& lhs, const Data& rhs )
{
return /* true if all members are equal */
};
int main( int argc, char* argv[] )
{
const BYTE source[][ DATA_SIZE ] =
{
{ 0x01, 0xfe, 0xaa, 0x01, 0xcc, 0x13 },
{ 0x02, 0xa1, 0x02, 0xbb, 0x02, 0xdd }
}
// how should this be done?
std::vector< Data > data_list( source[ 0 ], source[ countof( source) - 1 ] );
ASSERT( data_list[ 0 ] == Data( source[ 0 ] ) );
ASSERT( data_list[ 1 ] == Data( source[ 1 ] ) );
return 0;
}
有没有办法在没有for
循环迭代data
数组中的每个项目并调用push_back
的情况下执行此操作?
答案 0 :(得分:3)
你可以做的最少的改变是:
std::vector< Data > data_list(
&source[ 0 ],
&source[ countof( source) ] );
答案 1 :(得分:1)
以下是使用Boost.Array的方法:
#include <cstddef>
#include <cassert>
#include <vector>
#include <boost/array.hpp>
typedef unsigned UINT;
typedef unsigned char BYTE;
std::size_t const DATA_SIZE = 6;
struct Data
{
UINT a;
BYTE b, c, d;
Data() : a(), b(), c(), d() { }
Data(boost::array<BYTE, DATA_SIZE> const& data)
: a(data[0] << 16 | data[1] << 8 | data[2]),
b(data[3]),
c(data[4]),
d(data[5])
{ }
};
inline bool operator ==(Data const& lhs, Data const& rhs)
{
return lhs.a == rhs.a
&& lhs.b == rhs.b
&& lhs.c == rhs.c
&& lhs.d == rhs.d;
}
int main()
{
boost::array<boost::array<BYTE, DATA_SIZE>, 2> const source =
{{
{{ 0x01, 0xfe, 0xaa, 0x01, 0xcc, 0x13 }},
{{ 0x02, 0xa1, 0x02, 0xbb, 0x02, 0xdd }}
}};
std::vector<Data> data_list(source.begin(), source.end());
assert(data_list[0] == Data(source[0]));
assert(data_list[1] == Data(source[1]));
}