如何从PHP中的外部必需文件访问常量?

时间:2012-05-21 15:42:43

标签: php oop constants required class-constants

如果我将常量保留在类代码中,我有这个类我可以使用,但我想从外部文件访问它们,用户可以注释或取消注释c常量值。

这种方式效果很好,但我不希望用户在代码中翻找:

class passwordStringHandler
{

# const PWDALGO = 'md5';
# const PWDALGO = 'sha1';
# const PWDALGO = 'sha256';
# const PWDALGO = 'sha512';
const PWDALGO = 'whirlpool';

  /* THIS METHOD WILL CREATE THE SALTED USER PASSWORD HASH DEPENDING ON WHATS BEEN
    DEFINED    */

function createUsersPassword()
{

$userspassword = 'Te$t1234';

$saltedpassword='';    

if ((defined('self::PWDALGO')) && (self::PWDALGO === 'md5'))
{
    $saltedpassword = md5($userspassword . $this->pwdsalt);
    echo("The salted md5 generated hash is: " . $saltedpassword . "<br>");
    return $saltedpassword;

}elseif ((defined('self::PWDALGO')) && (self::PWDALGO === 'sha1')){
    $saltedpassword = sha1($userspassword . $this->pwdsalt);
    echo("The salted sha1 generated hash is: " . $saltedpassword . "<br>");
    return $saltedpassword;

}elseif ((defined('self::PWDALGO')) && (self::PWDALGO === 'sha256')){
    $saltedpassword = hash('sha256', $userspassword . $this->pwdsalt);
    echo("The salted sha256 generated hash is: " . $saltedpassword . "<br>");
    return $saltedpassword;

}elseif ((defined('self::PWDALGO')) && (self::PWDALGO === 'sha512')){
    $saltedpassword = hash('sha512', $userspassword . $this->pwdsalt);
    echo("The salted sha512 generated hash is: " . $saltedpassword . "<br>");
    return $saltedpassword;

}elseif ((defined('self::PWDALGO')) && (self::PWDALGO === 'whirlpool')){
    $saltedpassword = hash('whirlpool', $userspassword . $this->pwdsalt);
    echo("The salted whirlpool generated hash is: " . $saltedpassword . "<br>");
    return $saltedpassword;

}

else

    echo("No password algro is defined! Edit the [<strong>PWDALGO</strong>] options in the <strong>systemConfiguration.php</strong><br>");  
    return false;

}

这可以正常工作,因为它被硬编码到类文件中:

我想用它来工作:

require ("../configs/systemConfiguration.php");   
class passwordStringHandler
{

如果定义了PWDALGO,我一直在if / else语句中找到else。

或者这样

class passwordStringHandler
{
require ("../configs/systemConfiguration.php");

我不知道这是否可行,因为我一直收到错误,我认为你不能在类范围内包含或要求文件。

将来如果我开始工作,我想要一个安装脚本检查服务器以查看可用的加密类型,并列出供用户选择的首选加密方法,然后设置它自动为他们。并且稍后可以从管理控制面板更改加密方法。

1 个答案:

答案 0 :(得分:1)

听起来您希望这些常量跨越对象(类),而仅限于passwordStringHandler类。

如果 ,我建议您使用define()代替const

像这样:

<强> systemconfiguration.php

define('PWDALGO', 'whirlpool');

<强> passwordStringHandler.php

require ("../configs/systemConfiguration.php");

class passwordStringHandler
{
    if ((defined('PWDALGO')) && (PWDALGO === 'md5'))

更多信息: define() vs const