如何使用Quartz XML插件声明一次性简单触发器?

时间:2012-05-21 14:35:00

标签: quartz-scheduler

我正在尝试设置一个工作,使其在我的调度程序第一次启动时运行,然后在每天的午夜运行一次。这是我的工作和触发器的XML。每天一次触发工作,但一次性触发不起作用。

    <job>
      <name>MyJob</name>
      <group>MyJobGroup</group>
      <job-type>MyScheduledJob, MyJobAssembly</job-type>
      <description>My job, yo</description>
      <durable>true</durable>
      <recover>false</recover>
    </job>
    <trigger>
      <cron>
        <name>MyTrigger</name>
        <group>MyTriggerGroup</group>
        <job-name>MyJob</job-name>
        <job-group>MyJobGroup</job-group>
        <cron-expression>0 0 0 1/1 * ? *</cron-expression>
      </cron>
        <simple>
            <name>MyOneTimeTrigger</name>
            <group>MyTriggerGroup</group>
            <description>Run once at startup, G</description>
            <misfire-instruction>SmartPolicy</misfire-instruction>
            <volatile>false</volatile>
            <job-name>MyJob</job-name>
            <job-group>MyJobGroup</job-group>
            <repeat-count>0</repeat-count>
            <repeat-interval>0</repeat-interval> 
      </simple>
    </trigger>

1 个答案:

答案 0 :(得分:2)

无法正常工作我想你的意思是触发器永远不会触发。也许是因为它没有延迟它会失败?如何在将来的某个时间添加<start-time-seconds-in-future/>呢?

<simple>
        <name>MyOneTimeTrigger</name>
        <group>MyTriggerGroup</group>
        <description>Run once at startup, G</description>
        <misfire-instruction>SmartPolicy</misfire-instruction>
        <volatile>false</volatile>
        <job-name>MyJob</job-name>
        <job-group>MyJobGroup</job-group>
        <start-time-seconds-in-future>60</start-time-seconds-in-future>
        <repeat-count>0</repeat-count>
        <repeat-interval>0</repeat-interval> 
</simple>

如果它对你有用,你必须知道你可能认为是错误或功能的东西:如果你重新启动服务器,因为触发器已经被触发并被删除,它将再次触发。请参阅:Quartz XML plugin reschedules fired triggers after restart