我编写了以下代码我在编译这部分代码时解决了一个难题
#include <stdio.h>
int main ()
{
int a[10],b[10],c[10];
int i,j,k,l;
a[10]={"21","33","12","19","15","17","11","12","34","10"};
b[10]={"10","15","9","13","16","21","15","32","29","7"};
c[10]={"11","8","3","6","1","4","6","20","19","3"};
l=sizeof(a)/sizeof(a[0]);
for (i=0;i<=l;i++)
{
}
}
给我错误
array.c: In function ‘main’:
array.c:7:8: error: expected expression before ‘{’ token
array.c:8:8: error: expected expression before ‘{’ token
array.c:9:8: error: expected expression before ‘{’ token
为什么错误会在这里?
答案 0 :(得分:7)
您的代码中存在几个问题:
正确的代码行将是:
int a[10] = {21,33,12,19,15,17,11,12,34,10};
答案 1 :(得分:1)
您正在将数组的第11个元素设置为数组。
试试这个:
int a[10] = {21,33,12,19,15,17,11,12,34,10};
答案 2 :(得分:0)
类型不匹配:您正在将字符文字字符串设置为int
。这是禁忌。
您正在访问一个超出数组末尾的内容 - 一个经典的逐个错误。
答案 3 :(得分:0)
这是int数组不要'为数字加上引号
c[10]={11,8,3,6,1,4,6,20,19,3};