Question

下面的这个选择框会在提交表单后记住并突出显示-one-选择。但是，当我将其设为多个时，它在提交后不会突出显示任何选项。有关如何实现这一点的任何想法？

提前致谢。

<?php
$options_amount = array("0","1","2","3","4","5","6","7","8","9","10+");
$no_way = $_GET['no_way'];
?>

<select class="postform" name="no_way[]" multiple size="5">
<option <?php if ($no_way == 'all') { ?>selected="selected"<?php }?> value="all">Any</option>
<?php
foreach ($options_amount as $option) {
?><option <?php if ($no_way == $option) { ?>selected="selected"<?php }?> value="<?php echo $option; ?>"><?php echo $option; ?></option><?php }?>
</select>

Answer 1

$_GET['no_way']仅处理您必须使用$_GET['no_way[]']和in_array($option, $no_way)

的单个参数

Answer 2

我不确定这是否有帮助，但您是否有可能尝试使用selected代替selected="selected"？

<option <?php if ($no_way == $option) { ?> selected<?php }?> value="<?php echo $option; ?>"><?php echo $option; ?></option>

Answer 3

这对我有用：

<?php
$options_amount = array("0","1","2","3","4","5","6","7","8","9","10+");
$no_way = $_GET['no_way'];
?>
<select class="postform" name="no_way[]" multiple size="5">
<option <?php if (in_array("all",$no_way)) { ?>selected="selected"<?php }?> value="all">Any</option>
<?php
foreach ($options_amount as $option) {
?><option <?php if (in_array($option,$no_way)) { ?>selected="selected"<?php }?> value="<?php echo $option; ?>"><?php echo $option; ?></option><?php }?>
</select>

提交后突出显示表单上的多个选择

3 个答案: