这个SQLAlchemy交叉有什么问题?

时间:2012-05-20 09:39:58

标签: sql sqlalchemy

我正在尝试与下面的2个查询相交,但是我收到了这个错误:

  

ProgrammingError :( ProgrammingError)(1064,“你的错误   SQL语法;查看与MySQL服务器对应的手册   在'INTERSECT SELECT附近使用正确语法的版本   user_checkpoint.id AS user_checkpoint_id,user_checkpoint.user_'at   第4行“)'SELECT anon_1.user_checkpoint_id AS   anon_1_user_checkpoint_id,anon_1.user_checkpoint_user_id AS   anon_1_user_checkpoint_user_id,anon_1.user_checkpoint_checkpoint_id   AS anon_1_user_checkpoint_checkpoint_id,   anon_1.user_checkpoint_date_added AS anon_1_user_checkpoint_date_added   \ nFROM(SELECT user_checkpoint.id AS user_checkpoint_id,   user_checkpoint.user_id AS user_checkpoint_user_id,   user_checkpoint.checkpoint_id AS user_checkpoint_checkpoint_id,   user_checkpoint.date_added AS user_checkpoint_date_added \ nFROM   user_checkpoint INNER JOIN检查点ON checkpoint.id =   user_checkpoint.checkpoint_id INNER JOIN用户AS user_1 ON   user_checkpoint.user_id = user_1.id INNER JOIN facebook_user AS   facebook_user_1 ON facebook_user_1.id = user_1.facebook_user_id INNER   JOIN friend_connection ON friend_connection.fb_user_to =   facebook_user_1.id INNER JOIN facebook_user ON facebook_user.id =   friend_connection.fb_user_from INNER JOIN用户ON   user.facebook_user_id = facebook_user.id \ nWHERE user.id!=%s AND   checkpoint.creator = user_1.id AND checkpoint.demo =%s INTERSECT   SELECT user_checkpoint.id AS user_checkpoint_id,   user_checkpoint.user_id AS user_checkpoint_user_id,   user_checkpoint.checkpoint_id AS user_checkpoint_checkpoint_id,   user_checkpoint.date_added AS user_checkpoint_date_added \ nFROM   user_checkpoint INNER JOIN检查点ON checkpoint.id =   user_checkpoint.checkpoint_id \ nWHERE checkpoint.creator!=%s AND   checkpoint.demo =%s)AS anon_1 ORDER BY checkpoint.date_created DESC   \ n LIMIT%s'(185L,0,185L,0,1)

    #get checkpoints from users with friends
    FriendUserCheckpoint, FriendFacebookUser, FriendUser = aliased(UserCheckpoint), aliased(FacebookUser), aliased(User)
    q = (db.session.query(UserCheckpoint).
         join(Checkpoint, Checkpoint.id == UserCheckpoint.checkpoint_id).
         join(FriendUser, FriendUser.id == UserCheckpoint.user_id).
         join(FriendFacebookUser, FriendFacebookUser.id == FriendUser.facebook_user_id).
         join(FriendConnection, FriendConnection.fb_user_to == FriendFacebookUser.id).
         join(FacebookUser, FacebookUser.id == FriendConnection.fb_user_from).
         join(User, User.facebook_user_id == FacebookUser.id).
         filter(User.id != user_obj.id).
         filter(Checkpoint.creator == FriendUser.id).
         filter(Checkpoint.demo == False)
         )

    #get checkpoints from users without friends
    p = (db.session.query(UserCheckpoint).
         join(Checkpoint, Checkpoint.id == UserCheckpoint.checkpoint_id).
         filter(Checkpoint.creator != user_obj.id).
         filter(Checkpoint.demo == False)
         )

    w = q.intersect(p)

    return w.order_by(desc(Checkpoint.date_created)).limit(limit).all()

我该如何解决?谢谢!

1 个答案:

答案 0 :(得分:0)

您的查询问题是order_by:您尝试按查询中不在的列进行排序。生成的SQL查询如下所示:

SELECT anon_1.col1, anon_1.col2, ...
FROM (
    SELECT  <UserCheckpoint columns>
    FROM    UserCheckpoint
    ... (joins, filters etc)


    INTERSECT

    SELECT  <UserCheckpoint columns>
    FROM    UserCheckpoint
    ... (joins, filters etc)
) anon_1
ORDER BY checkpoint.date_created DESC -- @note: here is the problem

如您所见,外部查询在其源表列表中没有checkpoint表(其中只包含一个 anon_1)。删除order_by,我认为您的查询可以正常运行。

如果您需要order_by,请更改查询以返回date_created列,订购结果,然后删除该列:

q = (db.session.query(UserCheckpoint, Checkpoint.date_created).
...
p = (db.session.query(UserCheckpoint, Checkpoint.date_created).
...
return [uc for (uc, _) in w.order_by(desc(Checkpoint.date_created)).limit(limit).all()]