Jquery droppable获得多个可拖动的id

Question

当我跌入某个div时，我希望获得多个拖动的ID。 $(ui.draggable).attr('id');只获得第一个ID。

  Drag  <ul id="demo" > 
         <li id="1" ></li>
         <li id="2" ></li>
        <li id="3" ></li>
        </ul>

         <div class="drop"> drop here!! </div>

JQUERY

$(".drop").droppable({ 
                drop: function(event, ui) {

  var m_id = $(ui.draggable).attr('id');// only gets 1st id


      // i need to get multiple dragged id 

            1,2,3..     

            }       
            });

请帮帮我!! Thnks

Answer 1

var m_id = [];
$.each($(ui.draggable), function(i,e) {
   m_id.push(e.id);
});

//gives array with all ID's, could be joined with join()
//for comma seperated list

Answer 2

$("li").draggable({ revert: true });

$(".drop").droppable({
drop: function(event, ui) {
    var id = ui.draggable.attr("id");
    alert(id);
}
});