Question

我正在尝试用逗号分隔字符串“，”

例如：

"hi, welcome"  I would like to produce ["hi","welcome"]

但是：

"'hi,hi',hi" I would like to produce ["'hi,hi'","hi"]

"'hi, hello,yes','hello, yes','eat,hello'" I would like to produce ["'hi, hello,yes'","'hello, yes'","'eat,hello'"]

"'hiello, 332',9" I would like to produce ["'hiello, 332'","9"]

我不认为可以使用.split()函数，有没有人知道我可以这样做的方式，也许是正则表达式？

Answer 1

您可以将csv模块与quotechar参数一起使用，或者您可以转换输入以使用更标准的"字符作为其引号字符。

>>> import csv
>>> from cStringIO import StringIO
>>> first=StringIO('hi, welcome')
>>> second=StringIO("'hi,hi',hi")
>>> third=StringIO("'hi, hello,yes','hello, yes','eat,hello'")
>>> fourth=StringIO("'hiello, 332',9")
>>> rfirst=csv.reader(first,quotechar="'")
>>> rfirst.next()
['hi', ' welcome']
>>> rsecond=csv.reader(second,quotechar="'")
>>> rsecond.next()
['hi,hi', 'hi']
>>> rthird=csv.reader(third,quotechar="'")
>>> rthird.next()
['hi, hello,yes', 'hello, yes', 'eat,hello']
>>> rfourth=csv.reader(fourth,quotechar="'")
>>> rfourth.next()
['hiello, 332', '9']

>>> second=StringIO('"hi,hi",hi') # This will be more straightforward to interpret.
>>> r=csv.reader(second)
>>> r.next()
['hi,hi', 'hi']
>>> third=StringIO('"hi, hello,yes","hello, yes","eat,hello"')
>>> r=csv.reader(third)
>>> r.next()
['hi, hello,yes', 'hello, yes', 'eat,hello']

Answer 2

正如你要求的那样使用正则表达式：

import re

>>>pattern = re.compile(r"([^',]+,?|'[^']+,?')")
>>>re.findall(pattern, "hi, welcome")
['hi', 'welcome']

>>>re.findall(pattern, "'hi, hello,yes','hello, yes','eat,hello'")
["'hi, hello,yes'", "'hello, yes'", "'eat,hello'"]

>>>re.findall(pattern, "'hi,hi',hi")
 ["'hi,hi'", 'hi']

>>>re.findall(pattern, "'hiello, 332',9")
["'hiello, 332'", '9']

模式的第一部分[^',]+,?捕获没有引号且没有逗号的段。它最后可能有一个逗号，也可能没有（如果它是最后一段）。

第二部分'[^']+,?'捕获由引号括起的段。内部不应该有更多的引号，但它可能有逗号。

Answer 3

您可以使用csv reader ,作为分隔符，使用'作为quotechar。这似乎与你的期望相符。

Answer 4

直接在没有csv或re的情况下执行此操作不会有问题：

def splitstring(s):
    result = []
    for i, piece in enumerate(s.split("'")):
        if piece:
            if i % 2:  # odd pieces are between quotes
                result.append("'" + piece + "'")
            else:  # even pieces aren't
                for subpiece in piece.split(","):
                    if subpiece:
                        result.append(subpiece)
    return result

分裂为＆＃34;，＆＃34;在python中

4 个答案: