如何用Python对大文件进行排序?

时间:2012-05-19 14:15:59

标签: python sorting

我在activestate.com上发现了一些有用的代码来对大文件进行排序。我正在尝试在Ubuntu 10.04上的默认Python 2.6.5解释器上运行它。当我尝试在一个小测试文件上运行它时,我得到下面的错误跟踪。我在activestate.com上寻求帮助,但这个帖子已经沉默了18个多月。这里有没有人看到一个明显的解决方案?

感谢。

## {{{ http://code.activestate.com/recipes/576755/ (r3)
# based on Recipe 466302: Sorting big files the Python 2.4 way
# by Nicolas Lehuen

import os
from tempfile import gettempdir
from itertools import islice, cycle
from collections import namedtuple
import heapq

Keyed = namedtuple("Keyed", ["key", "obj"])

def merge(key=None, *iterables):
    # based on code posted by Scott David Daniels in c.l.p.
    # http://groups.google.com/group/comp.lang.python/msg/484f01f1ea3c832d

    if key is None:
        keyed_iterables = iterables
    else:
        keyed_iterables = [(Keyed(key(obj), obj) for obj in iterable)
                            for iterable in iterables]

    for element in heapq.merge(*keyed_iterables):
        yield element.obj


def batch_sort(input, output, key=None, buffer_size=32000, tempdirs=None):
    if tempdirs is None:
        tempdirs = []
    if not tempdirs:
        tempdirs.append(gettempdir())

    chunks = []
    try:
        with open(input,'rb',64*1024) as input_file:
            input_iterator = iter(input_file)
            for tempdir in cycle(tempdirs):
                current_chunk = list(islice(input_iterator,buffer_size))
                if not current_chunk:
                    break
                current_chunk.sort(key=key)
                output_chunk = open(os.path.join(tempdir,'%06i'%len(chunks)),'w+b',64*1024)
                chunks.append(output_chunk)
                output_chunk.writelines(current_chunk)
                output_chunk.flush()
                output_chunk.seek(0)
        with open(output,'wb',64*1024) as output_file:
            output_file.writelines(merge(key, *chunks))
    finally:
        for chunk in chunks:
            try:
                chunk.close()
                os.remove(chunk.name)
            except Exception:
                pass

错误追踪:

Traceback (most recent call last):
  File "./batch_sort.py", line 108, in <module>
    batch_sort(args[0],args[1],options.key,options.buffer_size,options.tempdirs)
  File "./batch_sort.py", line 54, in batch_sort
    output_file.writelines(merge(key, *chunks))
  File "./batch_sort.py", line 30, in merge
    yield element.obj
AttributeError: 'str' object has no attribute 'obj'

1 个答案:

答案 0 :(得分:2)

合并代码不正确。 如果您不提供密钥,则每个元素都是字符串而不是键控元组。

请改为尝试:

def merge(key=None, *iterables):
    # based on code posted by Scott David Daniels in c.l.p.
    # http://groups.google.com/group/comp.lang.python/msg/484f01f1ea3c832d

    if key is None:
        for element in heapq.merge(*iterables):
            yield element
    else:
        keyed_iterables = [(Keyed(key(obj), obj) for obj in iterable)
                        for iterable in iterables]
        for element in heapq.merge(*keyed_iterables):
            yield element.obj