我需要将以下格式给出的时间值字符串转换为秒。我正在使用python2.6
例如：
1.'00:00:00,000' -> 0 seconds
2.'00:00:10,000' -> 10 seconds
3.'00:01:04,000' -> 64 seconds
4. '01:01:09,000' -> 3669 seconds
我是否需要使用正则表达式来执行此操作？我尝试使用时间模块，但time.strptime('00:00:00,000','%I:%M:%S')扔了
ValueError: time data '00:00:00,000' does not match format '%I:%M:%S'
有人可以告诉我这是如何解决的吗？
编辑：
我认为
pt =datetime.datetime.strptime(timestring,'%H:%M:%S,%f')
total_seconds = pt.second+pt.minute*60+pt.hour*3600
给出正确的值..我使用了错误的模块
答案 0 :(得分：52)
对于Python 2.7：
>>> import datetime
>>> import time
>>> x = time.strptime('00:01:00,000'.split(',')[0],'%H:%M:%S')
>>> datetime.timedelta(hours=x.tm_hour,minutes=x.tm_min,seconds=x.tm_sec).total_seconds()
60.0
答案 1 :(得分：28)
我认为会有更多的pythonic方式：
timestr = '00:04:23'
ftr = [3600,60,1]
sum([a*b for a,b in zip(ftr, map(int,timestr.split(':')))])
输出为263秒。
我很想知道是否有人可以进一步简化它。
答案 2 :(得分：13)
没有进口
time = "01:34:11"
sum(x * int(t) for x, t in zip([3600, 60, 1], time.split(":")))
答案 3 :(得分：4)
看起来你愿意剥掉几分之一......问题是你不能使用'00'作为%I的小时
>>> time.strptime('00:00:00,000'.split(',')[0],'%H:%M:%S')
time.struct_time(tm_year=1900, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=0, tm_yday=1, tm_isdst=-1)
>>>
答案 4 :(得分：4)
要获得timedelta()，您应该减去1900-01-01：
>>> from datetime import datetime
>>> datetime.strptime('01:01:09,000', '%H:%M:%S,%f')
datetime.datetime(1900, 1, 1, 1, 1, 9)
>>> td = datetime.strptime('01:01:09,000', '%H:%M:%S,%f') - datetime(1900,1,1)
>>> td
datetime.timedelta(0, 3669)
>>> td.total_seconds() # 2.7+
3669.0
%H意味着输入不到一天，以支持超过一天的时差：
>>> import re
>>> from datetime import timedelta
>>> td = timedelta(**dict(zip("hours minutes seconds milliseconds".split(),
... map(int, re.findall('\d+', '31:01:09,000')))))
>>> td
datetime.timedelta(1, 25269)
>>> td.total_seconds()
111669.0
在Python 2.6上模拟.total_seconds()：
>>> from __future__ import division
>>> ((td.days * 86400 + td.seconds) * 10**6 + td.microseconds) / 10**6
111669.0
答案 5 :(得分：4)
struct WidgetTestEntryView : View {
var entry: Provider.Entry
var body: some View {
VStack {
HStack(spacing: 100){
Text("Favourite").foregroundColor(.white).font(.system(size: 16, weight: .bold, design: .default))
Image("Label").resizable().frame(width: 80, height: 15, alignment: /*@START_MENU_TOKEN@*/.center/*@END_MENU_TOKEN@*/)
}.frame(maxWidth: .infinity, maxHeight: 50, alignment: .center).background(Color.black).offset(y: -9)
HStack {
Spacer()
Button(action: {}) {
Image("").resizable().frame(width: 70, height: 70)
.cornerRadius(10)
.background(Color(red: 0.218, green: 0.215, blue: 0.25))
}.cornerRadius(10).onTapGesture {
let a = ViewController()
a.data.text = "Tap"
}
Button(action: {}) {
Image("").resizable().frame(width: 70, height: 70)
.cornerRadius(10)
.background(Color(red: 0.218, green: 0.215, blue: 0.25))
}.cornerRadius(10).onTapGesture {
let a = ViewController()
a.data.text = "Tap"
}
Button(action: {}) {
Image("").resizable().frame(width: 70, height: 70)
.cornerRadius(10)
.background(Color(red: 0.218, green: 0.215, blue: 0.25))
}.cornerRadius(10).onTapGesture {
let a = ViewController()
a.data.text = "Tap"
}
Button(action: {}) {
Image("").resizable().frame(width: 70, height: 70)
.cornerRadius(10)
.background(Color(red: 0.218, green: 0.215, blue: 0.25))
}.cornerRadius(10).onTapGesture {
let a = ViewController()
a.data.text = "Tap"
}
Spacer().frame(width: 10, height: 10, alignment: .center)
}.background(Color(red: 0.118, green: 0.118, blue: 0.15)).offset(y: -9)
}.frame(maxWidth: .infinity, maxHeight: .infinity, alignment: .center).background(Color(red: 0.118, green: 0.118, blue: 0.15))
}
}
答案 6 :(得分：3)
总是手工解析
>>> import re
>>> ts = ['00:00:00,000', '00:00:10,000', '00:01:04,000', '01:01:09,000']
>>> for t in ts:
... times = map(int, re.split(r"[:,]", t))
... print t, times[0]*3600+times[1]*60+times[2]+times[3]/1000.
...
00:00:00,000 0.0
00:00:10,000 10.0
00:01:04,000 64.0
01:01:09,000 3669.0
>>>
答案 7 :(得分：2)
import time
from datetime import datetime
t1 = datetime.now().replace(microsecond=0)
time.sleep(3)
now = datetime.now().replace(microsecond=0)
print((now - t1).total_seconds())
结果： 3.0
答案 8 :(得分：0)
受到sverrir-sigmundarson's评论的启发：
def time_to_sec(time_str):
return sum(x * int(t) for x, t in zip([1, 60, 3600], reversed(time_str.split(":"))))
答案 9 :(得分：0)
def time_to_sec(time):
sep = ','
rest = time.split(sep, 1)[0]
splitted = rest.split(":")
emel = len(splitted) - 1
i = 0
summa = 0
for numb in splitted:
szor = 60 ** (emel - i)
i += 1
summa += int(numb) * szor
return summa
答案 10 :(得分：0)
HH:MM:SS 和 MM:SS 的动态解决方案。如果要处理命令，请使用 split(',') 除以 1000 之类的，然后添加。
_time = 'SS'
_time = 'MM:SS'
_time = 'HH:MM:SS'
seconds = sum(int(x) * 60 ** i for i, x in enumerate(reversed(_time.split(':'))))
# multiple timestamps
_times = ['MM:SS', 'HH:MM:SS', 'SS']
_times = [sum(int(x) * 60 ** i for i, x in enumerate(reversed(_time.split(':')))) for _time in times]
答案 11 :(得分：0)
为什么不使用 functools.reduce？
from functools import reduce
def str_to_seconds(t):
reduce(lambda prev, next: prev * 60 + next, [float(x) for x in t.replace(',', '.').split(":")], 0)
一个函数，适用于 10,40、09:12,40 或 02:08:14,59。如果您使用 . 而不是 , 作为十进制符号，它会更简单：
def str_to_seconds(t):
reduce(lambda prev, next: prev * 60 + next, [float(x) for x in t.split(":")], 0)